Determining if a line is perpendicular in ##R^3##

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Homework Help Overview

The problem involves determining whether two lines in three-dimensional space, defined by specific points, are perpendicular to each other. The subject area pertains to vector geometry and properties of lines in \(\mathbb{R}^3\).

Discussion Character

  • Exploratory, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between the direction vectors of the lines, questioning how these vectors relate when the lines are perpendicular. The dot product is mentioned as a potential method for analysis. There is also a suggestion to consider the cross product as an alternative approach.

Discussion Status

The discussion is ongoing, with participants exploring different methods to determine perpendicularity. Some guidance has been offered regarding the use of dot and cross products, but there is no explicit consensus on the preferred approach. Additionally, a participant raises the consideration of whether the lines intersect, indicating a potential complexity in the problem.

Contextual Notes

There is an implication that the lines may be skew, which adds another layer to the discussion regarding their relationship in three-dimensional space.

Calpalned
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Homework Statement


Is the line through (-2, 4, 0) and (1, 1, 1) perpendicular to the line through (2, 3, 4) and (3, -1, -8)?

Homework Equations


R = R0 + tV (for each line)

The Attempt at a Solution


If the lines are parallel, then the V for the two equations will be proportional to each other. How are the two V's related if they are perpendicular?
 
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Calpalned said:

Homework Statement


Is the line through (-2, 4, 0) and (1, 1, 1) perpendicular to the line through (2, 3, 4) and (3, -1, -8)?

Homework Equations


R = R0 + tV (for each line)

The Attempt at a Solution


If the lines are parallel, then the V for the two equations will be proportional to each other. How are the two V's related if they are perpendicular?

Think dot product.
 
I see thank you, Dick.
 
You could also use the cross product if you prefer that.
 
Brian T said:
You could also use the cross product if you prefer that.

And you don't mind doing at least three times as much work...
 
:-p
 
You might also want to be sure that the lines intersect and thus are not skew lines.
 

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