Determining magnitude and direction of vectors

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SUMMARY

The discussion focuses on determining the magnitude and direction of the force vector F1, ensuring the resultant force is 800N directed vertically upward. The equation used is F1 = FR - F2 - F3, where F1x and F1y are calculated using horizontal and vertical components, respectively. The final calculations yield F1 as 274.7N and the angle θ as 29.1 degrees. This approach effectively utilizes vector resolution to solve for unknown forces.

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Homework Statement


Determine the magnitude and direction θ of F1 so that the resultant force is directed vertically upward and has a magnitude of 800N.

Homework Equations


F1=FR-F2-F3


The Attempt at a Solution


I have attached the question with diagram and my attempt at solving the question. I know that by using the equation above, F1=FR-F2-F3, however I am slightly confused as to obtaining the values for these vectors and how to approach doing that.
 

Attachments

  • Chp 2 - Q2.21 Problem.jpg
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  • Chp 2 - Q2.21 Problem WORKING.jpg
    Chp 2 - Q2.21 Problem WORKING.jpg
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Solve for F1x using the horizontal components, solve for F1y using vertical components, then take F1x and F1y to solve for F1 and θ
 
Thanks for your help Joffran, I managed to solve the problem with your help, I will add the working I used to solve it tomorrow
 
\SigmaFx=0 ----> 400cos30+F1x-(4/5)(600)=0 ----> F1x=133.6N
\SigmaFy=800 ----> 400sin30+F1y+(3/5)(600)=800 ----> F1y=240N

F1= (F1x^2+F2y^2)^.5 = (133.6^2+240^2)^.5=274.7N

tanθ=F1x/F1y=133.6/240

θ=tan^-1(133.6/240)=29.1
 

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