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Determining magnitude and direction of vectors

  1. Mar 13, 2012 #1
    1. The problem statement, all variables and given/known data
    Determine the magnitude and direction θ of F1 so that the resultant force is directed vertically upward and has a magnitude of 800N.

    2. Relevant equations
    F1=FR-F2-F3


    3. The attempt at a solution
    I have attached the question with diagram and my attempt at solving the question. I know that by using the equation above, F1=FR-F2-F3, however I am slightly confused as to obtaining the values for these vectors and how to approach doing that.
     

    Attached Files:

  2. jcsd
  3. Mar 13, 2012 #2
    Solve for F1x using the horizontal components, solve for F1y using vertical components, then take F1x and F1y to solve for F1 and θ
     
  4. Mar 14, 2012 #3
    Thanks for your help Joffran, I managed to solve the problem with your help, I will add the working I used to solve it tomorrow
     
  5. Mar 16, 2012 #4
    [itex]\Sigma[/itex]Fx=0 ----> 400cos30+F1x-(4/5)(600)=0 ----> F1x=133.6N
    [itex]\Sigma[/itex]Fy=800 ----> 400sin30+F1y+(3/5)(600)=800 ----> F1y=240N

    F1= (F1x^2+F2y^2)^.5 = (133.6^2+240^2)^.5=274.7N

    tanθ=F1x/F1y=133.6/240

    θ=tan^-1(133.6/240)=29.1
     
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