Determining Miles Traveled From Tire Diameter and Rotations.

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SUMMARY

The discussion focuses on calculating the distance traveled by a car based on tire diameter and rotations. A tire with a diameter of 28 inches, rotating 10,000 times, results in a distance of approximately 13.8833 miles. The calculation involves determining the circumference of the tire using the formula \(C = \pi \times d\) and applying the relationship \(s = r\theta\) to find linear displacement. The angular displacement \(\theta\) is calculated as \(10,000 \times 2\pi\) radians, leading to the same distance when using either method.

PREREQUISITES
  • Understanding of basic geometry, specifically circumference calculation
  • Familiarity with angular and linear displacement concepts
  • Knowledge of radians and their conversion from degrees
  • Ability to manipulate mathematical formulas
NEXT STEPS
  • Learn about angular displacement and its applications in physics
  • Study the relationship between linear and angular velocity using \(v = r\omega\)
  • Explore the concept of radians and their significance in circular motion
  • Practice solving problems involving tire rotations and distance calculations
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Students studying physics, automotive engineers, and anyone interested in understanding the relationship between tire rotations and distance traveled.

RidiculousName
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I am trying to figure out how to solve this equation. I have a car with tires of diameter 28", and they rotate 10,000 times. How far did I travel?

According to my textbook it's 13.9 miles.

I can figure it out by finding the circumference of the tire (87.96"), multiplying that by 10,000 (879600), dividing the product by the amount of inches in a mile (63360) to get 13.8826.

But, I am supposed to do it with this formula, $$s=r\theta$$
However, I'm not sure how to do that at all.
It is a formula to find the relation between a linear displacement and an angular displacement.
s = linear displacement
$$\theta$$ = angular displacement (and must be in radian form)
r = radius

I might be supposed to use $$v=r\omega$$
It is a formula to find the relation between a linear velocity and an angular velocity.
v = vertical speed
$$\omega$$ = angular speed (must be in radian form)
r = radius

How can I solve this problem using the formula $$s=r\theta$$?
 
Last edited:
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For a complete rotation, \theta= 2\pi radians. For a general angle of \theta there are \frac{\theta}{2\pi} rotations. Given a radius r, the circumference of a full circle is of course 2\pi r so that a rotation of \theta radians gives a distance of 2\pi r\frac{\theta}{2\pi}= r \theta.
 
Country Boy said:
For a complete rotation, \theta= 2\pi radians. For a general angle of \theta there are \frac{\theta}{2\pi} rotations. Given a radius r, the circumference of a full circle is of course 2\pi r so that a rotation of \theta radians gives a distance of 2\pi r\frac{\theta}{2\pi}= r \theta.

Thank you, but I don't understand how that answers my question.
 
"10000 rotations" is \theta= 10000(2\pi)= 20000\pi radians. The distance covered is \theta r= 20000\pi(14)= 280000\pi=879646 inches. That's just what you did, just with a slight change in the order of the multiplications. Your first calculated the circumfernce of the wheel, using 2\pi r then multiplied by 10000. Using r\theta you first calculate the total angular rotation, \theta[/b], in radians by multiplying 2\pi by 10000, and <b>then</b> multiply by r= 14 in.<br /> <br /> In other words, your method was to first multiply 2\pi r then multiply by 10000 while using &quot;r\theta&quot; you first find \theta by multiplying 10000(2\pi) and <b>then</b> multiply by r= 14.
 
Last edited:
What's wrong with keeping it simple:

u = wheel circumference = pi * 28 inches

10000 revolutions = u * 10000 inches

u * 10000 / (5280*12) = ~13.8833 miles
 
There's nothing wrong with that and, in fact, that was what the OP did. But his question was about using "r\theta" and that was what I was responding to.
 
Last edited:
Yer right CB...should be more careful...
A thousand apologies of which you may have one :)
 

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