Determining Miles Traveled From Tire Diameter and Rotations.

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Discussion Overview

The discussion revolves around calculating the distance traveled by a car based on tire diameter and the number of rotations. Participants explore different methods and formulas, including the relationship between linear and angular displacement.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a method to calculate distance using the circumference of the tire and the number of rotations, arriving at approximately 13.88 miles.
  • Another participant explains the formula $$s = r\theta$$, indicating that for a complete rotation, $$\theta = 2\pi$$ radians, and discusses how to apply this to find distance.
  • A subsequent reply reiterates the explanation of the relationship between rotations and radians, but the original poster expresses confusion about how it addresses their question.
  • Another participant calculates the total angular rotation as $$\theta = 10000(2\pi)$$ and shows how to derive the distance using $$r\theta$$, confirming the original calculation with a different approach.
  • One participant suggests a simpler method using the circumference directly, which aligns with the original poster's approach.
  • Another participant acknowledges the simplicity of the method but emphasizes the original poster's interest in using the $$r\theta$$ formula.

Areas of Agreement / Disagreement

Participants generally agree on the methods to calculate distance but express differing views on the preferred approach. The discussion remains unresolved regarding the clarity of the $$r\theta$$ application for the original poster.

Contextual Notes

Some participants note the importance of understanding the relationship between linear and angular measurements, but there are unresolved aspects regarding the original poster's confusion about the application of the formulas.

RidiculousName
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I am trying to figure out how to solve this equation. I have a car with tires of diameter 28", and they rotate 10,000 times. How far did I travel?

According to my textbook it's 13.9 miles.

I can figure it out by finding the circumference of the tire (87.96"), multiplying that by 10,000 (879600), dividing the product by the amount of inches in a mile (63360) to get 13.8826.

But, I am supposed to do it with this formula, $$s=r\theta$$
However, I'm not sure how to do that at all.
It is a formula to find the relation between a linear displacement and an angular displacement.
s = linear displacement
$$\theta$$ = angular displacement (and must be in radian form)
r = radius

I might be supposed to use $$v=r\omega$$
It is a formula to find the relation between a linear velocity and an angular velocity.
v = vertical speed
$$\omega$$ = angular speed (must be in radian form)
r = radius

How can I solve this problem using the formula $$s=r\theta$$?
 
Last edited:
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For a complete rotation, \theta= 2\pi radians. For a general angle of \theta there are \frac{\theta}{2\pi} rotations. Given a radius r, the circumference of a full circle is of course 2\pi r so that a rotation of \theta radians gives a distance of 2\pi r\frac{\theta}{2\pi}= r \theta.
 
Country Boy said:
For a complete rotation, \theta= 2\pi radians. For a general angle of \theta there are \frac{\theta}{2\pi} rotations. Given a radius r, the circumference of a full circle is of course 2\pi r so that a rotation of \theta radians gives a distance of 2\pi r\frac{\theta}{2\pi}= r \theta.

Thank you, but I don't understand how that answers my question.
 
"10000 rotations" is \theta= 10000(2\pi)= 20000\pi radians. The distance covered is \theta r= 20000\pi(14)= 280000\pi=879646 inches. That's just what you did, just with a slight change in the order of the multiplications. Your first calculated the circumfernce of the wheel, using 2\pi r then multiplied by 10000. Using r\theta you first calculate the total angular rotation, \theta[/b], in radians by multiplying 2\pi by 10000, and <b>then</b> multiply by r= 14 in.<br /> <br /> In other words, your method was to first multiply 2\pi r then multiply by 10000 while using &quot;r\theta&quot; you first find \theta by multiplying 10000(2\pi) and <b>then</b> multiply by r= 14.
 
Last edited:
What's wrong with keeping it simple:

u = wheel circumference = pi * 28 inches

10000 revolutions = u * 10000 inches

u * 10000 / (5280*12) = ~13.8833 miles
 
There's nothing wrong with that and, in fact, that was what the OP did. But his question was about using "r\theta" and that was what I was responding to.
 
Last edited:
Yer right CB...should be more careful...
A thousand apologies of which you may have one :)
 

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