Determining the coefficient of friction? (example inside)

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SUMMARY

The discussion focuses on determining the coefficient of friction between a physics textbook and a wooden ramp. The student conducts an experiment where a 1.2 kg textbook begins to slip at a 30-degree incline after 4.0 seconds. The coefficient of static friction is calculated using the formula μ_s = tan(θ), confirming the friend's initial calculation of 0.58 as correct. The relationship between gravitational force and static friction is emphasized as crucial for deriving the coefficient.

PREREQUISITES
  • Understanding of basic physics concepts, particularly forces and friction.
  • Familiarity with trigonometric functions, specifically tangent.
  • Knowledge of Newton's laws of motion.
  • Ability to perform calculations involving angles and forces.
NEXT STEPS
  • Study the derivation of the coefficient of static friction in inclined planes.
  • Learn about the differences between static and kinetic friction coefficients.
  • Explore the application of Newton's second law in friction problems.
  • Investigate experimental methods for measuring friction coefficients in various materials.
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of friction and inclined planes in mechanics.

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Homework Statement



A physics student is performing an experiment to determine the coefficient of friction between a physics textbook and a 2.5 m wooden ramp. He places the textbook, which has a mass of 1.2 kg, on the inclined ramp and gradually increases the angle of the incline. At an angle of 30 degrees, the textbook starts to slip. It slides down the ramp in 4.0 s. Determine the coefficient of friction.

Homework Equations





The Attempt at a Solution



Well i was working on it with my friend in class, and he came up with

friction = tan 30 degrees = 0.58

but then, I don't think that's all to it right? Any help please?
 
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The coefficient of static friction is indeed:

[tex]\mu_s=\tan\theta[/tex] where [tex]\theta[/tex] is the angle at which the block starts to slip.

You can work on deriving this yourself by starting with the following information:

At the angle where the block just starts to slip the component of gravity along the hill (x direction) much equal the force of static friction:

[tex]F_{gx}=F_{static f}[/tex]

Can you fill in for the forces above and solve for the coefficient? If you can, you should end up with the expression given by your friend.
 
Last edited:

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