Determining the direction of friction

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OmniNewton
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Homework Statement


Given the following diagram:
Structural diagram of a horizontal member AB pinned at A, with a box on top, a vertical member BC fixed below B, a force P applied at an angle at the right, and dimensions 1.5 m, 1.5 m, 1 m and 0.75 m.

When examining the FBD for member AB how does one determine the direction of friction at B? If surfaces B and C exhibit friction.

Homework Equations


N/A

The Attempt at a Solution


I know that impending motion for post BC is in the direction of P so friction acts opposite but I am unsure as to how one determines the impending motion for Member AB.
The answer provided is that the friction for member AB at surface B acts horizontally in the same direction as P.
 
OmniNewton said:

Homework Statement


Given the following diagram:
Structural diagram of a bent frame: horizontal member AB pinned at support A on the left with a box on top, joined at B to vertical member BC, with a 1 m and 0.75 m dimensions marked, a 1.5 m span on each side of B, and force P applied at a slanted collar on BC at its 5-12-13 slope.

When examining the FBD for member AB how does one determine the direction of friction at B? If surfaces B and C exhibit friction.

Homework Equations


N/A

The Attempt at a Solution


I know that impending motion for post BC is in the direction of P so friction acts opposite but I am unsure as to how one determines the impending motion for Member AB.
The answer provided is that the friction for member AB at surface B acts horizontally in the same direction as P.
The motion of member BC produced by the force P will create a friction force at B which opposes the motion of BC. That's the force which is shown on the FBD for member AB at point B.
 
SteamKing said:
The motion of member BC produced by the force P will create a friction force at B which opposes the motion of BC. That's the force which is shown on the FBD for member AB at point B.
Would the force at of friction on member BC not be in this direction <----- so why is Member AB's force of friction in this direction ------> ?
 
OmniNewton said:
Would the force at of friction on member BC not be in this direction <----- so why is Member AB's force of friction in this direction ------> ?
As long as member AB is not moving, the net force between AB and BC must equal zero. When you draw a FBD of AB, a force opposite the friction force on BC must be included to bring the net force on this member to zero.
 
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