Determining the distance difference of towers of a bridge

  • Thread starter Thread starter Xarzu
  • Start date Start date
  • Tags Tags
    Bridge Difference
Click For Summary
SUMMARY

This discussion focuses on calculating the distance difference between the tops of suspension bridge towers due to the Earth's curvature. Using the Golden Gate Bridge as a case study, the calculations involve the Earth's radius (6371000 meters), the height of the towers (227 meters), and the distance between the bases (1280 meters). The final result indicates a difference of approximately 4 millimeters, with a more accurate calculation yielding 45.6 millimeters. The solution utilizes the law of cosines and trigonometric principles to derive the necessary measurements.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Familiarity with the law of cosines for calculating distances in triangles.
  • Basic knowledge of Earth's geometry, including radius and circumference.
  • Proficiency in C++ programming for implementing calculations.
NEXT STEPS
  • Study the law of cosines in-depth for applications in real-world geometry problems.
  • Learn about spherical geometry and its implications for large-scale structures.
  • Explore C++ programming techniques for handling floating-point precision in calculations.
  • Research the effects of Earth's curvature on various engineering projects, particularly in bridge design.
USEFUL FOR

Engineers, mathematicians, and physics students interested in structural design and the effects of Earth's curvature on large constructions, particularly in the context of suspension bridges.

Xarzu

Homework Statement


Huge suspension bridges are build with the Earth's roundness in mind. The two towers are plumb line straight up and down and yet, because of their colossal size, they are a bit further apart at their tops than they are at their base. So, how can we calculate what this difference would be?

Here is the input data:

If we know the Earth's radius; the location of the base of the towers above sea level; The distance (from the center of each base of the tower) between the bases; and the height of the tower, how would we calculate the distance from the tops of the towers.

Homework Equations



I have seen a similar question answered once using something called "the law of cosines" where, if you know an angle and the length of two vectors, you can calculate the distances between the two vectors? I hope that helps and gives us a clue.

The Attempt at a Solution



Here I am not taking a stab at solving this on my own. The first thing I noticed in trying to solve this is that the lines forming the towers of the bridge can be thought of forming two right triangles back to back:

bridge%2001.jpg


Now, this is going way back for me -- I am talking decades -- since I last used this stuff. But, as I recall, Sine of an angle equals the Opposite side over the Hypotenuse. So, since we know what the Hypotenuse is. The angle is something we can figure out by taking the amount of the circle is taken up by the vectors.

bridge%2002.png

(this shows those helpful square thingies that indicate a right angle)

Now, I am going to actually put the mathematics to use with an actual example: the Golden Gate Bridge.

In order to get this as precise as possible, I am not going to google what the radius of the Earth is and then, separately, google what the circumference of the Earth is. If I do this, I am going to have messed up data because both numbers are going to be rounded. So in in order to get more precise data, I am going to use a given radius for the Earth and then calculate the circumference from that data.

radius = 6371000

We have to use corresponding radius and circumference in this equation in order for the results to be accurate since we are dealing with very small changes of measurements

Circumference = 2 π r
r is the radius of the circle
For π, I think this degree of precision will be enough 3.1415926535897932
radius is 6371000
So Circumference is 40030173.59201743

Now to get to work on a real life example. Take the golden gate bridge into consideration

Height of the tower
Height of tower above water: 746 ft = 227 m
the distance between the support is 1,280 m
since, on that small scale in comparison to the globe, there is little curvature, I am just going to use 1280 meters as a percentage of the circumference of the globe
40.075 million meters
40075000
So:
1280 x
-------- = -------
40030173.59201743 360
So:
40030173.59201743 x = 460800
So:
460800
x = -----------
40030173.59201743

0.0115113165557666 degrees
That is the whole angle. We have to split it in half now to get our angle for each of our right angle triangles:
0.0057556582778833 degrees
so, now for our Hypotenuse. Our hypotenuse is the radius of the Earth plus the height of the tower (6,371,000 meters plus 227) = 6371227
That is our H in "Sine 0.0057556582778833 = O/h"
With X being the unknown value (also known as "O" -- not zero, by the way -- it is the oposite side, the half distance between the tops of the towers ):

so
(0.000100342822) * 6371227 = (half the distance between the tops of the towers)
640.0228
doubled is
1,280.0456

So the difference in size between the top of the towers from the base is uh, 4 millimeters. In reality, it is a bit more. Where did I go wrong?
 
Physics news on Phys.org
This problem can be solved in one line . Think about similar triangles and a scaling factor .
 
I think I am going to try some C++ code and use "long double" variables
 
The one line calculation gives 45.6 mm . You got the right answer actually - you just slipped a place in reading the . 0456

All you essentially needed to solve the problem though was the scaling factor : Earths radius plus the column height / Earths radius
 
I solved this.

And I wrote some software in C++ to verify it.

I will share it here later

:)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 57 ·
2
Replies
57
Views
5K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
8K