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## Homework Statement

Two parallel plates labelled W (negative) and X (positive) are separated by 5.2 cm. The electric potential between the plates is 150 V. An electron starts from rest at time t

_{w}and reaches plate X at time t

_{x}. The electron continues through an opening in plate X and reaches point P at time t

_{P}.

**Determine the speed at t**

_{x}and t_{P}*e*= -1.6 x 10

^{-19}C

*m*= 9.1 x 10

_{e}^{-31}

## Homework Equations

V = kq

_{1}/ r

ΔV = ΔE/q

ε = ΔV / r

E

_{k}= 0.5mv

^{2}

## The Attempt at a Solution

I'm not sure how to determine v at t

_{w}and t

_{x}, but I did find the field strength: ε = 2884.6. We also know the electron starts from rest, so we could use the conservation of energy law to generate the following eq'n.

v

^{2}= 2m

^{-1}kq

_{1}q

_{2}(r

_{a}

^{-2 }- r

_{b}

^{2}). But we don't have a "q

_{2}" so I'm quite lost. Any help is appreciated!

God bless and thanks!