1. The problem statement, all variables and given/known data Two parallel plates 1.40 cm apart are equally and oppositely charged. An electron is released from rest at the surface of the negative plate and simultaneously a proton is released from rest at the surface of the positive plate. How far from the negative plate is the point at which the electron and proton pass each other? Known: Qe = -1.6 x 10-19 C Qp = 1.6 x 10-19 C me = 9.11 x 10-31 kg mp = 1.6 x 10-27 kg 2. Relevant equations a = qE/m d = 1/2*a*t2 3. The attempt at a solution Acceleration of electron ae = qeE / me Acceleration of proton ap = qpE / mp Distance of electron de = aet2 / 2 Distance of proton dp = apt2 / 2 Since I don't know time, I tried to eliminate it by t2 = 2de/ae and plugging it into distance formula but from there, I'm stuck on what to do.