Determining the force that is required

[x3lifelove]

A force acts an angle of 30.0 degrees relatives to the directions of displacement. What force is required to do 9600 J of work over a displacement of 25.0 m?




The solution that i am getting is 443 N of Force, but I'm not sure if i am doing it right though.

 

[jhae2.718]

If the force is constant, then $W = \mathbf{F} \cdot \mathbf{d}$. this gives W=Fdcos(30),
9600 Nm = F * 25cos(30) m
F = 443.4 N

 

[x3lifelove]

If the force is constant, then $W = F \cdot d$. this gives W=Fdcos(30),
9600 N = F * 25cos(30) m
F = 443.4 m

Thank you (:

 

[jhae2.718]

Note I messed up the unit originally, check my edited post. (Writing this on my phone)

 

[x3lifelove]

Note I messed up the unit originally, check my edited post. (Writing this on my phone)

Will do! Thank you again !