Determining the function using graphs

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Homework Statement


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Question #2.


Homework Equations


Not sure..That's what I'm supposed to figure out.


The Attempt at a Solution


Well I've graphed the points..That's about it hah.
Seems like a Log graph flipped on the x-axis.
 

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What if you assume that the dependence of the weight on distance follows some sort of power law i.e. [itex]w \propto r^a[/itex]? Can you think of something you can do to both quantities before plotting them that would make it easy to measure 'a' just by looking at the plot?
 
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I'm still not sure, I haven't done physics in about a year, and my mind is pretty much fresh..
The answers are ..
W = Kd^-2

K = 6.4x10^3 N(MR)^3

Please help me..I really don't understand anything.. :(
 
McKeavey said:
I'm still not sure, I haven't done physics in about a year, and my mind is pretty much fresh..
The answers are ..
W = Kd^-2

K = 6.4x10^3 N(MR)^3

Please help me..I really don't understand anything.. :(

What if you plotted both weight and distance on log scales (i.e. take log(w) and log(r)). What happens if you do that (just do it now to both sides of the equation). Can you see how this would make it possible to figure out that a = -2 just from the graph?
 
Ohh, yes hahh, I can see a = -2.
What about K?
 
McKeavey said:
Ohh, yes hahh, I can see a = -2.
What about K?

Well, if w = Kra, where K is some constant of proportionality, then it follows that:

log(w) = log(Kra) = alog(Kr) by the properties of logs.

But the log of a product is the sum of the logs of the individual factors so that:

alog(Kr) = alog(K) + alog(r)

So, if you plot log(w) vs. log(r), I think you can see that it will be linear and the slope of the line gives you a, while the offset (w-intercept) of the line gives you K.
 
Ugh what do you mean it will be linear when I plot log(w) vs. log(r)?

You mean line of best fit? :S
 
McKeavey said:
Ugh what do you mean it will be linear when I plot log(w) vs. log(r)?

You mean line of best fit? :S

I just showed you that log(w) varies linearly with log(r)! From my previous post:

log(w) = alog(r) + alog(K).

This is in the form of the standard equation for a straight line y = mx + b, with:
y = log(w),
m = a,
x = log(r), and
b = alog(K).

So, if you plot log(w) vs. log(r), you should get a straight line and you can measure its slope (m) and y-intercept (b). I don't know how to make it any clearer than that.
 
oh sorry sorry.
I got b = 3
and m = 4
(assuming these are wrong.. ugh)

What do I do with these?
Sorry I'm just really clueless at the moment..