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## Homework Statement

If the magnetic field of the wire is 2.5×10^−4 and the electron moves at 1.0×10^7 , what is the magnitude of the force exerted on the electron?

## Homework Equations

F=qvBsin(theta)

## The Attempt at a Solution

Sin(theta) = sin90 = 1

q = -1

v = 1e7

B = 2.5e-4

So, (-1)x(1e7)x(2.5e-4) = -2500, but that is not the right answer. What am I doing wrong?