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## Homework Statement

A current [tex]I[/tex] flows in a plane rectangular current loop with height a and horizontal sides b. The loop is placed into a uniform magnetic field [tex]\vec{B}[/tex] in such a way that the sides of length a are perpendicular to [tex]\vec{B}[/tex] (Part A 1 figure), and there is an angle [tex]\theta[/tex] between the sides of length [tex]b[/tex] and [tex]\vec{B}[/tex] (Part A 2 figure).

Calculate [tex]\tau[/tex], the magnitude of the torque about the vertical axis of the current loop due to the interaction of the current through the loop with the magnetic field.

Express the magnitude of the torque in terms of the given variables. You will need a trigonomeric function [e.g., [tex]\sin(\theta)[/tex] or [tex]\cos(\theta)[/tex]]. Use [tex]B[/tex] for the magnitude of the magnetic field.

Figure A 1

Figure A 2

## Homework Equations

[tex]\tau=IAB\sin(\theta)[/tex] (Assuming only 1 loop of wire)

## The Attempt at a Solution

I know that the area is [tex]a{\cdot}b[/tex], the current is [tex]I[/tex], the field is [tex]B[/tex], and the angle is [tex]\theta[/tex]. I put my answer in as

[tex]\tau=I(a{\cdot}b)B\sin(\theta)[/tex]

the feedback on my answer said to check my trigonometry, so I changed my answer to be the cosine instead of the sine and it was correct. Why is this? What is theta supposed to be the angle in between?