Determining the number of gear teeth?

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SUMMARY

The discussion centers on calculating gear sizes and the number of teeth required for a system with a shaft rotating at 250 RPM and delivering 850W of power. The input torque at the shaft is specified as 71Nm. It is concluded that the output torque is approximately 33Nm, suggesting a gear ratio of up to 71:33, with a recommendation of a 2:1 ratio for efficiency. However, the calculations indicate that to maintain 250 RPM with 71Nm torque, a load of 1860W is necessary, highlighting inconsistencies in the initial requirements.

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Isaac_DB19
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I have a system that consists of a shaft and two selected gears.

I want the shaft to be rotating at 250 RPM and to deliver an input power to the system of 850W.
The input torque at the shaft is 71Nm.

How can i use this information to determine how large my driving and driven gears will be, as well as determining the number of teeth that i would use on each gear.
 
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[I think you need to provide more information. A diagram or maybe a flowchart showing the inputs and outputs marking known requirements with their values and any known inputs.]

Edit: Oops! Misread your Q.
You want 850W at 250 RPM and have 71 Nm available.
Your output is about 33 Nm, so your gear ratio can be up to 71:33 depending on losses. Maybe 2:1 would be enough?
Your input shaft would therefore rotate at 125 RPM with atorque of 66 Nm + losses
 
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Isaac_DB19 said:
I want the shaft to be rotating at 250 RPM and to deliver an input power to the system of 850W. The input torque at the shaft is 71Nm.

That's not at all clear and looks inconsistent..

You say you "want the shaft to be rotating at 250 RPM" and the torque "at the shaft is 71Nm" ? That means you need a load on the shaft of 1860W.

250rpm = 26.2 Rads/S
Power = 26.2 * 71 = 1860W
 
Edit: sorry my spaces have not worked. It was tabulated.
I don't know how to delete the whole post, so I've deleted the mess! And I don't have time now to re post in another form.
 

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