Determining the uncertainity in Geiger Counter data

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Homework Help Overview

The discussion revolves around determining the uncertainty in Geiger Counter data, specifically focusing on the application of Poisson statistics to estimate uncertainty from count data obtained in a single trial. Participants explore the implications of using the square root of counts as a measure of uncertainty and its visibility in error bars.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of Poisson statistics for estimating uncertainty, questioning whether it is appropriate given the small size of the resulting error bars. There is also inquiry into how to handle uncertainty when only one trial has been conducted.

Discussion Status

The conversation is ongoing, with participants providing insights into the appropriateness of using Poisson for uncertainty estimation. Some express concerns about the significance of the small error bars, while others affirm that the approach taken is reasonable given the nature of the data.

Contextual Notes

Participants note that the counts range from 20,000 to 100,000, and there is a focus on the implications of having only one trial for the uncertainty calculations.

learningastronomy
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Homework Statement
I have a list of counts that are taken from a Geiger Counter based off only one trial. There were 20 runs taken with different voltages. The voltage ranged from 500 to 1000 and the counts ranged from 20,000 to 100,000.
Relevant Equations
Let c be counts therefore uncertainty is ##\sqrt{c}##.
From what I understand thus far is the counting involves Poisson therefore the uncertainty is just the square root of the counts, correct? But when I take the square root of the counts it produces a very small number compared to the count which makes it insignificant therefore the error bars that I want to produce aren't visible because the uncertainty is so small. Am I correct in using Poisson to measure the uncertainty? There was only one trial done.
 
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learningastronomy said:
Homework Statement:: I have a list of counts that are taken from a Geiger Counter based off only one trial. There were 20 runs taken with different voltages. The voltage ranged from 500 to 1000 and the counts ranged from 20,000 to 100,000.
Relevant Equations:: Let c be counts therefore uncertainty is ##\sqrt{c}##.

From what I understand thus far is the counting involves Poisson therefore the uncertainty is just the square root of the counts, correct? But when I take the square root of the counts it produces a very small number compared to the count which makes it insignificant therefore the error bars that I want to produce aren't visible because the uncertainty is so small. Am I correct in using Poisson to measure the uncertainty? There was only one trial done.
The description is not clear to me.

Is it that, on the basis that the process is Poisson, you want the uncertainty in the Poisson rate as deduced from a single count? My understanding is that if you estimate the parameter from a single Poisson count the standard error in that estimate is indeed the square root of the count. Yes, with such large counts this will be a relatively small number.
 
Last edited:
haruspex said:
The description is not clear to me.

Is it that, on the basis that the process is Poisson, you want the uncertainty in the Poisson rate as deduced from a single count? My understanding is that if you estimate the parameter from a single Poisson count the standard error in that estimate is indeed the square root of the count. Yes, with such large counts this will be a relatively small number.

The process does not have to be Poisson, I just assumed to use Poisson to compute the uncertainty. If there was only one trial in the experiment how do I solve for the uncertainty/error bars? Will Poisson suffice even though the uncertainty is so small it becomes insignificant?
 
learningastronomy said:
The process does not have to be Poisson, I just assumed to use Poisson to compute the uncertainty. If there was only one trial in the experiment how do I solve for the uncertainty/error bars? Will Poisson suffice even though the uncertainty is so small it becomes insignificant?
To get an answer you have to make an assumption about the nature of the distribution, and Poisson seems entirely reasonable.
I see no objection to what you have done. The error bars will really be that small.
 
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haruspex said:
To get an answer you have to make an assumption about the nature of the distribution, and Poisson seems entirely reasonable.
I see no objection to what you have done. The error bars will really be that small.
Oh I see, thank you!
 

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