Determining the width of a slit

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The discussion focuses on calculating the width of a slit and the distance between adjacent maxima in a single-slit interference pattern created by a laser with a wavelength of 560 nm. The central maximum is noted to be 5.0 cm wide, leading to the calculation of the distance between adjacent maxima as 0.025 m. Using the formula λ = wΔy / L, the width of the slit is determined to be 6.72 x 10^-5 m. There is some uncertainty regarding the accuracy of the Δy calculation, particularly concerning the central maximum's position. Overall, the calculations for both the slit width and the distance between maxima are presented, with a request for confirmation on their correctness.
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Homework Statement



A laser emitting light with a wavelength of 560nm is directed at a single slit, producing an interference pattern on a screen 3.0m away. The central maximum is 5.0cm wide. 10mks
Determine the width of the slit and the distance between adjacent maxima.[/B]

Homework Equations



λ = wΔy / L

The Attempt at a Solution



Given: Required: w, and https://www.physicsforums.com/file://localhost/Users/jefferyhewitt/Library/Group%20Containers/UBF8T346G9.Office/msoclip1/01/clip_image001.png λ = 560 nmL = 3.0m

m1 = 5.0cm

For the distance between adjacent maxima:

Δy = m1 / 2

Δy = 5.0cm / 2

Δy = 2.5cm

Δy = 0.025mthe distance between adjacent maxima is 0.025m.λ = wΔy / L

w = λL / Δy

w = (5.6 x10-7m)(3.0m) / (0.025m)w = 6.72 x10-5mTherefore, the width of the slit is 6.72 x10-5m.I'm pretty sure I have this right for calculating the slit width, but I'm not sure if I calculated the Δy value properly. any help is greatly appreciated.
 
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chef99 said:
the distance between adjacent maxima is 0.025m.
Only for some of them (the central maximum is not 0.025m away from any other maximum), but I guess that's what the question is asking about.
 
mfb said:
Only for some of them (the central maximum is not 0.025m away from any other maximum), but I guess that's what the question is asking about.
Thank you for your help!
 
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