- #1
UniPhysics90
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Deuteron is given by j(p)=1(+)
In my textbook it says that the observed parity of + for deuteron means that the orbital angular momentum quantum number, l, is even so is 0 or 2, and s=1.
However, looking back the textbook also says that for odd-odd nuclei, the parity is given by the product of the parities of the two odd shells by p=(-1)^l. If l was 1 in this case, for both cases, wouldn't this give a even parity to the nucleus? Then as j=1, s=0.
I've read somewhere (probably wikipedia) that it's preferable for the neutron and proton to have the same spin, which would mean l=0 or 2 is more favourable, but the book definitely makes it sound that it is the parity you can deduce l from.
Any help would be really appreciated!
In my textbook it says that the observed parity of + for deuteron means that the orbital angular momentum quantum number, l, is even so is 0 or 2, and s=1.
However, looking back the textbook also says that for odd-odd nuclei, the parity is given by the product of the parities of the two odd shells by p=(-1)^l. If l was 1 in this case, for both cases, wouldn't this give a even parity to the nucleus? Then as j=1, s=0.
I've read somewhere (probably wikipedia) that it's preferable for the neutron and proton to have the same spin, which would mean l=0 or 2 is more favourable, but the book definitely makes it sound that it is the parity you can deduce l from.
Any help would be really appreciated!