DI/dt & Moving Charge: Calculating Change

  • Thread starter Thread starter Kolahal Bhattacharya
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SUMMARY

The discussion focuses on calculating the rate of change of current (dI/dt) generated by a moving charge along the x-axis, represented by the equation J = ρv = qv²δ(r - vt). The user seeks clarification on how to derive dI/dt from the current density J, emphasizing that the current is not steady. It is established that dI/dt is directly influenced by the velocity (v) of the charge, indicating that an increase in v results in an increase in dI/dt.

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  • Understanding of electromagnetism concepts, specifically current density (J).
  • Familiarity with the equations of motion for charged particles.
  • Knowledge of calculus, particularly differentiation.
  • Basic principles of charge and current in physics.
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  • Study the derivation of current density (J) in electromagnetic theory.
  • Learn about the relationship between charge velocity and current in moving charges.
  • Explore calculus applications in physics, focusing on differentiation of current functions.
  • Investigate the implications of non-steady currents in circuit analysis.
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Physics students, educators, and professionals in electromagnetism, particularly those interested in the dynamics of moving charges and current calculations.

Kolahal Bhattacharya
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As we know,a single moving charge creats a current J=rho*v=qv^2*delta(r-vt) supposing that the charge moves along x axis.However,it is not a steady current.Making I=J.dS,how can we calculate the dI/dt?I suppose,it will depend on v in such a manner that if v increases,dI/dt will increase...Any help?(Note it's not a homework question)
 
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But it is a HOMEWORK/SCHOOLWORK-TYPE question, so it still belongs there.

Zz.
 

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