Diagonalization of metric matrix in general relativity

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Diagonalization of the metric matrix (g_{uv}) in general relativity is possible locally through a proper choice of coordinates, but not globally due to the non-flat nature of spacetime. While some metrics, like the Schwarzschild metric, are already diagonal, the Kerr metric presents challenges. The process of diagonalization can be achieved using methods such as Sylvester's Law of Inertia, but the specific components of the matrix must be known. The introduction of tetrads (4-bein) allows for a trivial metric in tangent space, eliminating the need for complex numbers. Overall, while diagonalization is feasible, its practical implications in general relativity require careful consideration.
exponent137
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1. Is its possible diagonalization of metric matrix (g_{uv}) in general relativity?

2. If we include imaginary numbers, can this help?
 
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It's possible to diagonalize the metric in a small region, by the proper choice of coordinates. It's not possible to diagonalize it everywhere, because space-time is not flat. It's rather like asking if it's possible to make an accurate map of the Earth's surface that correctly represents distances "to scale" without distortion, covering the entire surface. This is possible on a globe, but not possible on a flat sheet of paper.

I'm not sure where complex numbers come into the problem, perhaps you're asking some question other than the one I thought you were asking.
 
It's possible to diagonalize the metric in a small region, by the proper choice of coordinates. It's not possible to diagonalize it everywhere, because space-time is not flat. It's rather like asking if it's possible to make an accurate map of the Earth's surface that correctly represents distances "to scale" without distortion, covering the entire surface. This is possible on a globe, but not possible on a flat sheet of paper.

Flat is not the issue. The metric on the Earth's surface in the usual spherical polar coordinates *is* diagonal. The Schwarzschld metric is diagonal too.
 
Oooops. My remarks were mistakenly off-topic (about making the metric unity, not diagonal).

Offhand, I'm not sure what it takes to make a general metric diagonal - though the only non-diagonal metric I can think of offhand is the Kerr metric.
 
Every quadratic form (and hence every line element) can be written as a sum of N squares, where some of the squares have a minus sign in front, according to the signature of the quadratic form. So yes, the metric can always be diagonalized. However, the basis in which it diagonalizes is not always a coordinate basis.

Actually, what I've just described is the process of finding the orthonormal frames.
 
Say we are given a particular matrix that has the following form

<br /> G_{\alpha\beta}=<br /> \begin{pmatrix}<br /> 0 &amp; 0 &amp; 0 &amp; 0 \\<br /> 0 &amp; G_{11} &amp; G_{12} &amp; G_{13} \\<br /> 0 &amp; G_{21} &amp; G_{22} &amp; G_{23} \\<br /> 0 &amp; G_{31} &amp; G_{32} &amp; G_{33}<br /> \end{pmatrix}<br />

Is it possible to diagonalize this matrix using only a general algorithm, or must the components be known explicitly?
 
jfy4 said:
Say we are given a particular matrix that has the following form

<br /> G_{\alpha\beta}=<br /> \begin{pmatrix}<br /> 0 &amp; 0 &amp; 0 &amp; 0 \\<br /> 0 &amp; G_{11} &amp; G_{12} &amp; G_{13} \\<br /> 0 &amp; G_{21} &amp; G_{22} &amp; G_{23} \\<br /> 0 &amp; G_{31} &amp; G_{32} &amp; G_{33}<br /> \end{pmatrix}<br />

Is it possible to diagonalize this matrix using only a general algorithm, or must the components be known explicitly?
I used to know how to do this, 30 years ago. Look up "Sylvester's Law of Inertia".
 
jfy4 said:
Say we are given a particular matrix that has the following form

<br /> G_{\alpha\beta}=<br /> \begin{pmatrix}<br /> 0 &amp; 0 &amp; 0 &amp; 0 \\<br /> 0 &amp; G_{11} &amp; G_{12} &amp; G_{13} \\<br /> 0 &amp; G_{21} &amp; G_{22} &amp; G_{23} \\<br /> 0 &amp; G_{31} &amp; G_{32} &amp; G_{33}<br /> \end{pmatrix}<br />

Is it possible to diagonalize this matrix using only a general algorithm, or must the components be known explicitly?

Of course you can, using the same method you would use to diagonalize any 3x3 matrix.
 
So, because diagonalization is always possible, space-time of Minkowski can be generalized to general relativity. The question is only, if such changed space-time axes have any meaning?
 
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exponent137 said:
1. Is its possible diagonalization of metric matrix (g_{uv}) in general relativity?

2. If we include imaginary numbers, can this help?
By introducing the tetrad (4-bein) formalism you do something like that; the tetrad is a map between the manfold and its tangent space; on the tangent space you have a trivial (+---) metric. The tetrads can be used as dynamical variables instead of the metric. They have real components, so there is no need for complex numbers.
 

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