- #1
pylauzier
- 20
- 0
Homework Statement
A problem in my book asks the reader to evaluate lim x→0 xln(2x) using L'Hôpital.
Homework Equations
None
The Attempt at a Solution
I think I got it right but I simply wanted to make sure I did no illegal manipulations (I'm self-studying this stuff).
I started by substituting u = 1/x to get an undeterminate form suitable for L'Hôpital. By doing so, lim x→0 becomes lim u→∞
lim x→0 xln(2x) = lim u→∞ ln(2/u) / u
Applying L'Hôpital:
= lim u→∞ (-u)/2u2
= lim u→∞ (-1)/2u
= 0
I know that's the right answer, but did I make any mistakes? Also, was I allowed to switch lim x→0 by lim u→∞? Thanks in advance!