Dielectric Constant Computation

In summary, to calculate dielectric constant, you must use the area of the contactor and not the area of the plate. You must also use the distance between the contactor and the sample as the measure of thickness.
  • #1
cjX
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Homework Statement



Say, i have a setup as shown on the photo below

http://www.flickr.com/photos/47719498@N07/4375079183/

* setup also seen as attachment

how can i be able to compute for the dielectric constant provided it is not parallel plate and considering two different area is used. one is a circular contact and one is a square-shaped same size as the sample being analyzed.

given are the following:

Capacitance, measured connected with contactors
Area of the contactors, one circular, the other square
Distance - thickness of sample


Homework Equations



Using below Formula:
εr or k is the dielectric constant equivalent to the Capacitance (C ) divided by the Product of ε0, the electric constant and the ratio of Area (A) of the plates t0 their distance (d) between them.

εr = C/(ε0*(A/d))

ε0 = electric constant (8.854E-12)


The Attempt at a Solution



The above formula gives an unreal computed dielectric response to the sample being analyzed
 

Attachments

  • Setup.JPG
    Setup.JPG
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  • #2
can anyone help me pls...
 
  • #3
To calculate the capacity, you have to take the common area of the contactor and the plate. The dielectric constant of the substance does not depend on the shape of the substance.
 
  • #4
rl.bhat said:
To calculate the capacity, you have to take the common area of the contactor and the plate. The dielectric constant of the substance does not depend on the shape of the substance.

Sir, meaning to say that only the effective area of both contactor shall be used. if that is the case, the circular contactor area will be used as the reference for computation instead of the plate.

now, capacitance measurement is available but can you pls. help provide direct formula to be used in order to compute for the dielectric constant ? also, fringing lines would happen since the area of the plate is larger than that of the circular contactor. fields would be generated on the area where the circular contactor would not be able to cover.


appreciate your positive response sir.
 
  • #5
Function of the capacitor is to store the charges. This function is not affected by the fringe lines, because the bound charges on the lower plate are confined in the area equal to the area of the contactor.
Your formula for the dielectric constant is correct.
 
  • #6
rl.bhat said:
Function of the capacitor is to store the charges. This function is not affected by the fringe lines, because the bound charges on the lower plate are confined in the area equal to the area of the contactor.
Your formula for the dielectric constant is correct.


just to calibrate, i will use the circular contactor for Area on the formula for dielectric constant computation.

now, have told my professor about this and he does not believe that there will be no fringing lines.

can you suggest other formula to be used in calculating the dielectric constant with different area of parallel contactors ? kindly advise for any or reference materials..


thankies
 
  • #7
now, capacitance measurement is available but can you pls. help provide direct formula to be used in order to compute for the dielectric constant ?
If you can measure the capacitance, then dielectric constant = capacitance with sample/capacitance without sample
 
  • #8
I doubt anyone can tell you off-hand to what extent the fringing fields will make your system deviate from the ideal parallel plate equation. The equation should give you a good result, perhaps within 10% maybe. I am not aware of anyone doing any true analytical analysis of this kind of problem, maybe if you did a literature search you may find something since this is probably a fairly common situation. That is, I am sure there are texts and papers about the deviations that arise when you have finite parallel plate conductors. Barring that, you could always use a numeric simulation to find your answer, like an FEM or MOM analysis but those are rather involved. In addition, they are more useful for calculating the expected capacitance with a given dielectric configuration. You are doing the opposite, you have the capacitance and wish to find the dielectric from this. So you would probably have to do a variety of results to find out the capacitance as a function of the dielectric and then interpolate from those results what your dielectric constant is.
 

1. What is the definition of dielectric constant?

The dielectric constant, also known as relative permittivity, is a measure of a material's ability to store electrical energy in an electric field. It is the ratio of the electric flux density produced in a material to the electric flux density produced in a vacuum under the same conditions.

2. How is dielectric constant computed?

Dielectric constant is computed by measuring the capacitance of a material with the same dimensions and electrodes, first with the material present and then with the material replaced by air or vacuum. The dielectric constant is then calculated as the ratio of the two capacitance values.

3. What factors can affect the dielectric constant of a material?

The dielectric constant of a material can be affected by factors such as the type of material, its molecular structure and composition, temperature, and frequency of the applied electric field. The presence of impurities or defects in the material can also affect its dielectric constant.

4. What are the applications of dielectric constant computation?

Dielectric constant computation has various applications in industries such as electronics, telecommunications, and materials science. It is used to design and optimize electronic components, determine the insulation properties of materials, and study the behavior of materials in electric fields.

5. How does dielectric constant affect the behavior of materials in an electric field?

The dielectric constant of a material affects its ability to store electrical energy, which in turn affects its response to an applied electric field. A higher dielectric constant means that the material can store more energy, leading to a stronger response to an external electric field. This can result in phenomena such as polarization, which is important in various electrical applications.

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