Dielectric Constant: Solving Homework Problems

Click For Summary
SUMMARY

The discussion centers on calculating the dielectric constant of a material inserted between capacitor plates while connected to a 5V battery. The user determined that the dielectric constant (K) is 1.5 by using the formula K = C2/C1, where C2 is the charge with the dielectric (7.5μC) and C1 is the charge without the dielectric (5μC). The conclusion confirms that the dielectric constant is a unitless ratio, effectively describing the impact of the dielectric on capacitance.

PREREQUISITES
  • Understanding of capacitor fundamentals, including charge and capacitance.
  • Familiarity with dielectric materials and their effects on capacitance.
  • Knowledge of basic electrical equations, particularly those involving capacitors.
  • Ability to perform unit analysis and ratio calculations.
NEXT STEPS
  • Study the relationship between capacitance and dielectric materials in detail.
  • Learn about energy storage in capacitors and how it relates to dielectric constants.
  • Explore the implications of dielectric constants in real-world applications, such as capacitors in circuits.
  • Investigate how varying dielectric materials affect the performance of capacitors in different environments.
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering students, and anyone interested in understanding the principles of capacitors and dielectrics in electrical circuits.

jamesjd
Messages
13
Reaction score
0

Homework Statement



A slab of dielectric is now inserted between the plates, the battery still being connected. 7.5μC of additional charge flows from one plate, through the battery and onto the other plate. What is the dielectric constant of the dielectric material?

Homework Equations



A 1.0μF air-spaced capacitor is connected across the terminals of a 5V battery. What charge will be deposited on the plates? How much energy is stored by the charged capacitor?

Which i calculated the charge to be 5E-6C

The Attempt at a Solution



K = C2/C1

= 7.5E-6 / 5E-6

= 1.5

Is this correct and are there any units?
 
Physics news on Phys.org
thank you, are my calculations correct or am i missing something?
 

Similar threads

Calculating Electric Displacement in Dielectric-Filled Capacitor Slabs
  • · Replies 1 ·
Replies
1
Views
2K
Confusion with constant voltage and dielectric
  • · Replies 21 ·
Replies
21
Views
3K
Dual plate capacitor with two dielectric slabs
  • · Replies 2 ·
Replies
2
Views
3K
Finding the bound charge in a dielectric
  • · Replies 10 ·
Replies
10
Views
6K
Changes in capacitor after dielectric inserted
  • · Replies 17 ·
Replies
17
Views
3K
Capacitors: find the dielectric constant
  • · Replies 2 ·
Replies
2
Views
2K
Graduate Energy changes upon insertion of a solid dielectric in a capacitor
  • · Replies 2 ·
Replies
2
Views
2K
Two-layer dielectric, four-capacitor model vs three-capacitor model
  • · Replies 5 ·
Replies
5
Views
1K
How Does Inserting Different Dielectric Materials Affect Capacitor Performance?
  • · Replies 9 ·
Replies
9
Views
3K
Find Dielectric Constant from Parallel Plate Capacitor Problem
  • · Replies 1 ·
Replies
1
Views
2K