Dielectric polarization and capacitance

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SUMMARY

The discussion centers on the relationship between dielectric polarization and capacitance in capacitors, particularly in the context of liquid crystals. It is established that as a dielectric becomes more polarized, the internal electric field reduces the net electric field across the capacitor, which paradoxically allows for increased charge storage. The key equation governing this relationship is C = Q / V, where an increase in capacitance indicates a non-linear behavior, as seen in components like varactor diodes. The participants clarify that charge movement involves repulsion from the plates rather than attraction.

PREREQUISITES
  • Understanding of dielectric materials and their properties
  • Familiarity with the equation C = Q / V for capacitors
  • Knowledge of electric fields and charge movement
  • Basic principles of non-linear capacitance in semiconductor devices
NEXT STEPS
  • Research the effects of dielectric polarization on capacitance in various materials
  • Study the behavior of varactor diodes and their applications in tuning circuits
  • Explore the mathematical derivation of capacitance in non-linear systems
  • Investigate the role of liquid crystals in electronic components and their unique properties
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Students and professionals in electrical engineering, physicists studying material properties, and anyone interested in the principles of capacitance and dielectric behavior in capacitors.

Tjornan
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Hello all! My friend and I are having a bit of a discussion. We did an experiment on liquid crystals as dielectrics with changing voltage, and we came across some weird conclusions (capacitance decreased with increasing voltage? odd. Our theory is that liquid crystals don't act as normal dielectrics).

But that's not the purpose of this post! We are discussing why the capacitance of a capacitor increases if the dielectric becomes more polarized. He says he understands it, but his explanation doesn't make any sense to me.

I understand that an internal electric field inside the dielectric decreases the net electric field across the capacitor, but I don't understand how this increases the amount of charge the capacitor can store. Shouldn't a decrease in the net electric field across the capacitor decrease the number of electrons that can be stored on the capacitor, since it is the electric field that attracts them to the other side in the first place? Since the field is less, the attractive force is less. But common physics tells me my layman attempt at a solution is wrong!

Can someone elucidate? If you can explain it in terms of the movement of electrons, that would be best! I already understand how the increase in capacitance is derived from the equations.

Thanks!
 
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A linear capacitor obeys a simple rule, C = Q / V.
If the slope of the Q / V relationship, (= capacitance), changes then the capacitor is non-linear.
Reverse biassed semiconductor junctions can have non-linear capacitance. An example is the varactor diode.
http://en.wikipedia.org/wiki/Varicap
 
Welcome to PF;
Tjornan said:
My friend and I are having a bit of a discussion. We did an experiment on liquid crystals as dielectrics with changing voltage, and we came across some weird conclusions (capacitance decreased with increasing voltage? odd. Our theory is that liquid crystals don't act as normal dielectrics).
This is correct - for a given value of "normal" - see post #2. But this is not your question.

We are discussing why the capacitance of a capacitor increases if the dielectric becomes more polarized. He says he understands it, but his explanation doesn't make any sense to me.

I understand that an internal electric field inside the dielectric decreases the net electric field across the capacitor, but I don't understand how this increases the amount of charge the capacitor can store. Shouldn't a decrease in the net electric field across the capacitor decrease the number of electrons that can be stored on the capacitor, since it is the electric field that attracts them to the other side in the first place?
You appear to have this backwards.
Charge is moved from one plate to the other against the electric field between the plates.
Charges are repelled from their plates, not attracted.
 

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