Diff eq - LT Discontinuous Sources HW

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SUMMARY

This discussion focuses on solving differential equations involving discontinuous sources using the partial fraction method. The participant expresses frustration with the complexity of this method and seeks alternative strategies. A solution is provided, demonstrating the conversion of the function ##Y_1(s) = \frac{1}{(s+3)(s-4)(s-8)}## into partial fractions, followed by the application of the inverse Laplace transform to obtain ##y_1(t)##. The final solution is presented as ##5 u(t-9)y_1(t-9)##, highlighting the effectiveness of this approach in simplifying the problem.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with partial fraction decomposition techniques
  • Knowledge of inverse Laplace transforms
  • Basic concepts of discontinuous sources in differential equations
NEXT STEPS
  • Study advanced techniques in Laplace transforms
  • Learn about the application of the Heaviside step function in differential equations
  • Explore alternative methods for solving differential equations, such as the convolution theorem
  • Practice problems involving partial fraction decomposition in various contexts
USEFUL FOR

Students and professionals in engineering and mathematics, particularly those dealing with differential equations and control systems, will benefit from this discussion.

Arij
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Homework Statement


15whzic.png


Homework Equations


2j495qh.png

The Attempt at a Solution


this is my attempt, I figured this would be easier than typing.
2hhipmq.jpg


any how, I find partial fraction method is so time consuming and very algebraically complicated, is there a trick or another method I could use to make this easier?

thanks
 
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Arij said:

Homework Statement


15whzic.png


Homework Equations


2j495qh.png

The Attempt at a Solution


this is my attempt, I figured this would be easier than typing.
2hhipmq.jpg


any how, I find partial fraction method is so time consuming and very algebraically complicated, is there a trick or another method I could use to make this easier?

thanks

Convert ##Y_1(s) = \frac{1}{(s+3)(s-4)(s-8)}## to partial fractions, then multiply by ##5 e^{-9s}## later; better still, find the inverse of ##Y_1(s)## as ##y_1(t)##; the solution is then ##5 u(t-9)y_1(t-9)##.

The partial fractions can be found easily (but still with some algebra) by applying successively the identities
$$\frac{1}{(s-a)(s-b)} = \frac{1}{a-b} \left[ \frac{1}{s-a} - \frac{1}{s-b} \right] \: \text{if} \; a \neq b$$
 
Ray Vickson said:
Convert ##Y_1(s) = \frac{1}{(s+3)(s-4)(s-8)}## to partial fractions, then multiply by ##5 e^{-9s}## later; better still, find the inverse of ##Y_1(s)## as ##y_1(t)##; the solution is then ##5 u(t-9)y_1(t-9)##.

The partial fractions can be found easily (but still with some algebra) by applying successively the identities
$$\frac{1}{(s-a)(s-b)} = \frac{1}{a-b} \left[ \frac{1}{s-a} - \frac{1}{s-b} \right] \: \text{if} \; a \neq b$$
That was so much help
Ray Vickson said:
5u(t−9)y1(t−9
I used this and worked like miracles for few questions, I was just confused of changing to and from the t-c.
 
Arij said:
That was so much help

*************************************************
I am glad. It does not always work, but when it does it makes life a lot easier.
*************************************************

I used this and worked like miracles for few questions, I was just confused of changing to and from the t-c.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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