1. The problem statement, all variables and given/known data Find a particular solution of the given equation. [tex] y^''' + 4y^' = 3x-1[/tex] 2. Relevant equations [tex] r^3 + 4r = 0 [/tex] [tex] r = 0, r = 2i, r = -2i[/tex] 3. The attempt at a solution [tex]y(x) = Ax-B[/tex] [tex]y^'(x) = A[/tex] [tex]y^''(x) = 0[/tex] [tex]y^'''(x) = 0[/tex] The answer is: [tex]y(x)=(3/8)x^2 - (1/4)x[/tex] But I'm not sure how they came to this, please help!!!