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## Homework Statement

Find a particular solution of the given equation.

[tex] y^''' + 4y^' = 3x-1[/tex]

## Homework Equations

[tex] r^3 + 4r = 0 [/tex]

[tex] r = 0, r = 2i, r = -2i[/tex]

## The Attempt at a Solution

[tex]y(x) = Ax-B[/tex]

[tex]y^'(x) = A[/tex]

[tex]y^''(x) = 0[/tex]

[tex]y^'''(x) = 0[/tex]

The answer is:

[tex]y(x)=(3/8)x^2 - (1/4)x[/tex]

But I'm not sure how they came to this, please help!!!