- #1
mr_coffee
- 1,629
- 1
Hello everyone I'm lost on how they want me to approach this:
Find the two values of k for which
y(x) = e^{kx}
is a solution of the differential equation
y'' - 16 y' + 60 y = 0.
smaller value =?
larger value = ?
I did the following:
y(x) = e^(kx);
y' = ke^(kx);
y'' = k^2e^(kx);
(k^2e^(kx)) - 16(ke^(kx)) + 60(e^(kx)) = 0;
is there a sysematic way to solve this problem rather then just trying to randomly guess numbers? i tried the randomly guessing k values and it isn't working out
Any help would be great!
thanks!
Find the two values of k for which
y(x) = e^{kx}
is a solution of the differential equation
y'' - 16 y' + 60 y = 0.
smaller value =?
larger value = ?
I did the following:
y(x) = e^(kx);
y' = ke^(kx);
y'' = k^2e^(kx);
(k^2e^(kx)) - 16(ke^(kx)) + 60(e^(kx)) = 0;
is there a sysematic way to solve this problem rather then just trying to randomly guess numbers? i tried the randomly guessing k values and it isn't working out
Any help would be great!
thanks!