rshalloo
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Homework Statement
So I'm having a bit of trouble getting my head around this concept and was hoping someone would be able to shed some light on it.
I know the definition. i.e free charge isn't bound to a nucleus whereas bound is. But physically what difference does this make. i.e are free charges only found on conductors, or are the chagres that I would have started learning electrostatics with (griffiths 2-3) free charges aswell?
Homework Equations
D = ε_0 E + P
The Attempt at a Solution
I would say that yes the original charges are free and that bound charges only exist in dielectrics but I'm not sure if this is the right approach.
Thanks