Difference in Potential and Resistance in Series Circuits

Click For Summary

Homework Help Overview

The discussion revolves around a series circuit involving five similar lamps connected to a voltage source of 550 V. Participants are exploring how to determine the potential difference across each lamp, as well as the resistance of individual lamps and the total resistance of the circuit.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of Ohm's Law to find the resistance and potential difference across the lamps. There is uncertainty about whether to use the total voltage or the voltage across individual lamps for calculations. Some participants question the correctness of the original poster's reasoning and calculations.

Discussion Status

Some participants have confirmed parts of the original poster's reasoning, while others have pointed out potential misunderstandings regarding the use of total voltage versus individual lamp voltage. There is ongoing exploration of how to apply formulas correctly in the context of series circuits.

Contextual Notes

Participants are navigating assumptions about voltage distribution in series circuits and the implications of using total versus individual resistances in their calculations.

demode
Messages
30
Reaction score
0
1. Five similar lamps are connected in series to a source providing a difference of potential of 550 V.
A) What is the difference of potential across each lamp?
B) If the current flowing in the circuit is 1.10 A, what is the resistance of each lamp?
C) What is the resistance of all five lamps?

2. R = V/I
A) To find the difference of potential across each lamp, I believe you would divide the source difference of potential by 5, giving you 110
B) To find the resistance, Ohm's Law can be re-arranged, giving you R = V/I. I believe dividing the SOURCE different of potential by the given current would give you (550v / 1.10 a) = 500 ohms

C) Last but not least, to find the total resistance, we would just multiply the resistance found in part B times 5 (for each lamp) giving us 2500 ohms

Have I made a mistake in my thought process? If someone could confirm my attempt, it would be appreciated.
 
Physics news on Phys.org
looks good to me.
 
Ok, I'm only unsure for parts B and C, because I didn't know whether to use the difference of potential solved in part A for parts b and c.
 
demode said:
Ok, I'm only unsure for parts B and C, because I didn't know whether to use the difference of potential solved in part A for parts b and c.

If you use the total potential difference, 550 V, the resistance you find is the total resistance of all the lamps, not the resistance of one lamp.
 
Part A is correct.

Part B gives the total resistance of the circuit.

Part C. there's a mistake. If you know V for each bulb is 110V and the current through it is 1.10A. Therefore R = V/I = 110/1.10 = ?

EDIT: didnt mean to step on your toes nrqed.
 
er right. Blew that one on this end. assumed he used the V across the lamp to get R, not the total V.
 
Thanks so much for your help.. It seems I have one more queston..

If you know the resistance of two resistors (connected in series) as well as the current flowing through them, how do you find the difference of potential across each resistor?
 
demode said:
Thanks so much for your help.. It seems I have one more queston..

If you know the resistance of two resistors (connected in series) as well as the current flowing through them, how do you find the difference of potential across each resistor?

V = IR**********filling in space
 
D'oh.. I should have thought of that.

Would I use that formula for EACH resistor, or could I use it once using the Total resistance?

**EDIT**
Retract that, using the total resistance would give me the same result if I just added together the two differences of potential I'm solving for.
 
Last edited:
  • #10
If you want to find the voltage across individual resistances then you use V = IR, where R is individual resistance. This can also be applied on a larger scale.
 

Similar threads

Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
14
Views
906
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 23 ·
Replies
23
Views
3K