- #1

Jan Vesely

- 4

- 0

- Homework Statement
- Ok, this is a problem from our textbook and I really do not know how to approach this one, I searched the interned a could not find something similar. I cannot just use Ohm’s Law because the resistor is changing in value. Any help would be appreciated :).

- Relevant Equations
- U = I * R

In the circuit, two identical incandescent lamps are connected to a voltage source of voltage U = 6.0 V via an ohmic resistor of magnitude

R= 8.2 are connected to a voltage source of voltage U = 6.0 V.

As electrical components, incandescent lamps do not behave like ohmic resistors. When current flows through a lamp, it heats up and changes its electrical resistance. The table gives the current 1 flowing through an incandescent lamp for the incandescent lamps used, at various voltages U dropped across the lamp.

2.a) Determine the amperage / of the current flowing through the resistor when the switch is open.

2.b) Determine how high the voltage of the battery must be so that a current of the same intensity / flows through the resistor when the switch is closed.

current of the same amperage / flows through the resistor.

R= 8.2 are connected to a voltage source of voltage U = 6.0 V.

As electrical components, incandescent lamps do not behave like ohmic resistors. When current flows through a lamp, it heats up and changes its electrical resistance. The table gives the current 1 flowing through an incandescent lamp for the incandescent lamps used, at various voltages U dropped across the lamp.

2.a) Determine the amperage / of the current flowing through the resistor when the switch is open.

2.b) Determine how high the voltage of the battery must be so that a current of the same intensity / flows through the resistor when the switch is closed.

current of the same amperage / flows through the resistor.

V: 0,17 | 0,67 | 1,18 | 1,66 | 2,33 | 3,05 | 3,85 | 4,73 | 5,37 | 6,00 |

mA: 83 | 132 | 175 | 208 | 251 | 290 | 329 | 368 | 395 | 420 |

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