Difference in Potential and Resistance in Series Circuits

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SUMMARY

The discussion focuses on calculating the difference of potential and resistance in a series circuit with five lamps connected to a 550 V source. Each lamp experiences a potential difference of 110 V, derived by dividing the total voltage by the number of lamps. The resistance of each lamp is calculated using Ohm's Law, yielding 100 ohms when the current is 1.10 A. The total resistance of the circuit is 500 ohms, which is the sum of the individual resistances of the lamps.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Knowledge of series circuits and their properties
  • Ability to perform basic electrical calculations
  • Familiarity with voltage, current, and resistance concepts
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  • Learn about calculating total resistance in series and parallel circuits
  • Explore the implications of voltage drops across individual components in series
  • Study advanced applications of Ohm's Law in complex circuits
  • Investigate the effects of varying current on resistance in real-world scenarios
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Electrical engineering students, educators teaching circuit theory, and hobbyists working on electronics projects involving series circuits.

demode
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1. Five similar lamps are connected in series to a source providing a difference of potential of 550 V.
A) What is the difference of potential across each lamp?
B) If the current flowing in the circuit is 1.10 A, what is the resistance of each lamp?
C) What is the resistance of all five lamps?

2. R = V/I
A) To find the difference of potential across each lamp, I believe you would divide the source difference of potential by 5, giving you 110
B) To find the resistance, Ohm's Law can be re-arranged, giving you R = V/I. I believe dividing the SOURCE different of potential by the given current would give you (550v / 1.10 a) = 500 ohms

C) Last but not least, to find the total resistance, we would just multiply the resistance found in part B times 5 (for each lamp) giving us 2500 ohms

Have I made a mistake in my thought process? If someone could confirm my attempt, it would be appreciated.
 
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looks good to me.
 
Ok, I'm only unsure for parts B and C, because I didn't know whether to use the difference of potential solved in part A for parts b and c.
 
demode said:
Ok, I'm only unsure for parts B and C, because I didn't know whether to use the difference of potential solved in part A for parts b and c.

If you use the total potential difference, 550 V, the resistance you find is the total resistance of all the lamps, not the resistance of one lamp.
 
Part A is correct.

Part B gives the total resistance of the circuit.

Part C. there's a mistake. If you know V for each bulb is 110V and the current through it is 1.10A. Therefore R = V/I = 110/1.10 = ?

EDIT: didnt mean to step on your toes nrqed.
 
er right. Blew that one on this end. assumed he used the V across the lamp to get R, not the total V.
 
Thanks so much for your help.. It seems I have one more queston..

If you know the resistance of two resistors (connected in series) as well as the current flowing through them, how do you find the difference of potential across each resistor?
 
demode said:
Thanks so much for your help.. It seems I have one more queston..

If you know the resistance of two resistors (connected in series) as well as the current flowing through them, how do you find the difference of potential across each resistor?

V = IR**********filling in space
 
D'oh.. I should have thought of that.

Would I use that formula for EACH resistor, or could I use it once using the Total resistance?

**EDIT**
Retract that, using the total resistance would give me the same result if I just added together the two differences of potential I'm solving for.
 
Last edited:
  • #10
If you want to find the voltage across individual resistances then you use V = IR, where R is individual resistance. This can also be applied on a larger scale.
 

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