Difference in radius, same power and intensity?

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The discussion centers on the relationship between acoustic power and intensity as sound propagates through different spherical surfaces. The power remains constant at 0.12 W for both a 1.0m and a 5.0m radius due to the same sound source. However, the intensity decreases with distance, as calculated using the formula I = P/4∏r^2. This concept clarifies that while the power output of the source does not change, the intensity diminishes as one moves further away. Understanding this principle resolves the confusion regarding the differing intensity values at varying distances.
SPcle
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Homework Statement


How much acoustic power propagates through a spherical surface (sound source in centre) with radius equal to 1.0m? with radius equal to 5.0m?

I = 10^-2 W/m^2
r = 1.0m or 5.0m
f = 50kHz
t = 2.0*10^-3s
IL = 100dB

Homework Equations


I = P/4∏r^2


The Attempt at a Solution


i figured out that when r = 1.0, power must be 1.3*10^-1W. However, when I work out the intensity when r = 5.0, i get:

10^-2 = P/4*∏*25
(10^-2)(4*∏*25) = P
3.1W = P

However, the answer states that the power for both spheres is 0.12W... What concept am I not understanding?
 
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It is the same sound source which produces I = 10^-2 W/m^2 at unit distance, so its power is 0.13 W. The same power propagates through any concentric spherical surface, with less and less intensity.

ehild
 
ooh, i see. so basically the power stays the same because it's the same sound source (a bat, in this case), but the intensity becomes a lot less in distance. i understand now, thanks!
 
SPcle said:
ooh, i see. so basically the power stays the same because it's the same sound source (a bat, in this case), but the intensity becomes a lot less in distance. i understand now, thanks!

You understood it quick:smile: You are welcome.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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