The solution to a linear differential equation is, y=exp(ax). If a is complex ,say a=b+ic, then the period is T=2pi/c. My question is, if a is in polar form, a=r*exp(iθ), how is the period then T=2pi/θ.(adsbygoogle = window.adsbygoogle || []).push({});

Any help would be great,

Thank,

Will

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# Difference of period between cartesian and polar eigenvalue representation

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