- #1
mototsykl
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This may seem elementary, but it's been awhile since I've done heavy algebra work.
I used the quadratic formula to get this equation:
[itex]\mu = (\pm \sqrt{1 - 8x^{2}} - 1)/2[/itex]
and I'm trying to simplify to:
[itex]\mu = (\sqrt{1 + 8x^{2}} - 1)/2[/itex]
If anyone could just point me to any resources that could give me the answer, or let me know of some obscure algebraic property I've forgotten, that'd be great!
I'm pretty sure you can't distribute negatives into a square root, but x | x > 1.00, so any value of x would give a negative answer under the radical, and I'm left with an imaginary number.
I also tried breaking down the difference of two squares into its factors, but that only works when I add another factor to compensate for 8, and makes it more messy than before.Thanks.
I used the quadratic formula to get this equation:
[itex]\mu = (\pm \sqrt{1 - 8x^{2}} - 1)/2[/itex]
and I'm trying to simplify to:
[itex]\mu = (\sqrt{1 + 8x^{2}} - 1)/2[/itex]
If anyone could just point me to any resources that could give me the answer, or let me know of some obscure algebraic property I've forgotten, that'd be great!
I'm pretty sure you can't distribute negatives into a square root, but x | x > 1.00, so any value of x would give a negative answer under the radical, and I'm left with an imaginary number.
I also tried breaking down the difference of two squares into its factors, but that only works when I add another factor to compensate for 8, and makes it more messy than before.Thanks.
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