- #1
octol
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Consider the linear operator T on [tex]\mathcal{C}^2[/tex] with the matrix
[tex] \bmatrix 2 && -3\\3 && 2 \endbmatrix [/tex]
in the standard basis. With the basis vectors
[tex] \frac{1}{\sqrt{2}} \bmatrix i \\ 1 \endbmatrix, \quad \frac{1}{\sqrt{2}} \bmatrix -i \\ 1 \endbmatrix [/tex]
this operator can be written
[tex] \bmatrix 2+3i && 0\\0 && 2-3i \endbmatrix [/tex]
My question is, how can I see this? How can I see that the two matrices represent the same operator? I understand that what these matrices represent is how they transform the basis vectors, e.g., for the first matrix above we have
[tex] T \bmatrix 1 \\ 0 \endbmatrix = 2 \bmatrix 1 \\ 0 \endbmatrix + 3 \bmatrix 0 \\ 1 \endbmatrix. [/tex]
Was along time since I took a class in linear algebra so I have totally forgotten how to think about these things.
[tex] \bmatrix 2 && -3\\3 && 2 \endbmatrix [/tex]
in the standard basis. With the basis vectors
[tex] \frac{1}{\sqrt{2}} \bmatrix i \\ 1 \endbmatrix, \quad \frac{1}{\sqrt{2}} \bmatrix -i \\ 1 \endbmatrix [/tex]
this operator can be written
[tex] \bmatrix 2+3i && 0\\0 && 2-3i \endbmatrix [/tex]
My question is, how can I see this? How can I see that the two matrices represent the same operator? I understand that what these matrices represent is how they transform the basis vectors, e.g., for the first matrix above we have
[tex] T \bmatrix 1 \\ 0 \endbmatrix = 2 \bmatrix 1 \\ 0 \endbmatrix + 3 \bmatrix 0 \\ 1 \endbmatrix. [/tex]
Was along time since I took a class in linear algebra so I have totally forgotten how to think about these things.