Differential equation for bank balance

Click For Summary

Homework Help Overview

The discussion revolves around modeling a bank balance situation using a differential equation. The original poster presents a scenario where Peter borrows $100,000 and repays it at a rate of $12,000 per year, with interest compounded continuously at a rate of 7.25% per year. The goal is to establish a continuous model for the balance owed over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to formulate the balance as a function of time, incorporating both the repayment and interest accumulation. Some participants suggest using a continuous model to simplify the calculations, while others question how the repayment rate is integrated into the differential equation.

Discussion Status

Participants are exploring different formulations of the differential equation, with some providing alternative expressions for the balance over time. There is an ongoing examination of how to accurately represent the continuous nature of repayments and interest accumulation, but no consensus has been reached yet.

Contextual Notes

There is a discussion about the assumptions involved in treating repayments as continuous rather than discrete, and how this affects the formulation of the differential equation. The initial condition of the balance is also noted.

Xamfy19
Messages
60
Reaction score
0
Hello, I need help for the following question:
Peter borrowed $100,000 from bank and he pays back at a rate of $12,000 per year. The bank charges him interest at a rate of 7.25% per year compounded continuously. Make a continuous model of his situation using differential equation involving dB/dt where B = B(t) is the balance he owes the bank at time t.

I thought the B(t) is something like
B(t) = (100000-12000t) + Sum(n from 1 to t) [100000-12000(n-1)]*0.0725.

But, I am not sure yet. Thanks for help...
 
Physics news on Phys.org
B(t) = B_{0}e^{rt}
\frac{dB}{dt} = rB_{0}e^{rt} = rB(t)
 
Thanks, but how the payback rate is taken into account?
 
The point of writing it as a differential equation- i.e. a differentiable function, is to avoid having to take into account individual payments as you do with your sum. Treat the problem as if money is being paid back continuously through the year (at a rate of 12000 per year) while interest is accumulating continously (and so at (e0.0725t[/itex]- 1)B).

\frac{dB}{dt}= (e^{0.075t}- 1)B- 12000
with initial value B(0)= 100000.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
5K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
13
Views
3K