Differential equation ( help with solving it )

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SUMMARY

The discussion focuses on solving the differential equation dy/dx = (y²-1)/(x²-1) using the method of separation of variables. The user successfully separated the variables to reach the equation dy/(y²-1) = dx/(x²-1) and integrated both sides, resulting in ln(y-1) - ln(y+1) = ln(x-1) - ln(x+1). The key insight provided was the application of partial fractions to simplify the integration process, specifically using the decomposition 1/(x²-1) = A/(x+1) + B/(x-1).

PREREQUISITES
  • Understanding of differential equations, specifically first-order separable equations.
  • Familiarity with integration techniques, including natural logarithms.
  • Knowledge of partial fraction decomposition in algebra.
  • Basic calculus concepts related to derivatives and integrals.
NEXT STEPS
  • Study the method of separation of variables in greater detail.
  • Learn about partial fraction decomposition and its applications in integration.
  • Explore advanced integration techniques, including integration by substitution.
  • Practice solving various types of differential equations to reinforce understanding.
USEFUL FOR

Students studying calculus, particularly those focusing on differential equations, as well as educators looking for effective methods to teach integration techniques.

ismail amre
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Homework Statement


dy/dx = (y2-1)/(x2-1)

Homework Equations


The Attempt at a Solution



I tried to solve it by method of separation of variable and i reached
dy/(y2-1)=dx/(x2-1)
then by integrating both side i should have this answer which i got from the solution manual which is ln (y-1) - ln (y+1) = ln (x-1) - ln(x+1) .
i understand all the solution except the integration of any side of this equation dy/(y2-1)=dx/(x2-1)
 
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ismail amre said:

Homework Statement


dy/dx = (y2-1)/(x2-1)


Homework Equations





The Attempt at a Solution



I tried to solve it by method of separation of variable and i reached
dy/(y2-1)=dx/(x2-1)
then by integrating both side i should have this answer which i got from the solution manual which is ln (y-1) - ln (y+1) = ln (x-1) - ln(x+1) .
i understand all the solution except the integration of any side of this equation dy/(y2-1)=dx/(x2-1)

Use partial fractions: 1/(x2-1) = A/(x+1) + B/(x-1)
 
LCKurtz said:
Use partial fractions: 1/(x2-1) = A/(x+1) + B/(x-1)

thank you very much i didn't think about that
 

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