Differential equation ( help with solving it )

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ismail amre
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Homework Statement


dy/dx = (y2-1)/(x2-1)

Homework Equations


The Attempt at a Solution



I tried to solve it by method of separation of variable and i reached
dy/(y2-1)=dx/(x2-1)
then by integrating both side i should have this answer which i got from the solution manual which is ln (y-1) - ln (y+1) = ln (x-1) - ln(x+1) .
i understand all the solution except the integration of any side of this equation dy/(y2-1)=dx/(x2-1)
 
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ismail amre said:

Homework Statement


dy/dx = (y2-1)/(x2-1)


Homework Equations





The Attempt at a Solution



I tried to solve it by method of separation of variable and i reached
dy/(y2-1)=dx/(x2-1)
then by integrating both side i should have this answer which i got from the solution manual which is ln (y-1) - ln (y+1) = ln (x-1) - ln(x+1) .
i understand all the solution except the integration of any side of this equation dy/(y2-1)=dx/(x2-1)

Use partial fractions: 1/(x2-1) = A/(x+1) + B/(x-1)
 
LCKurtz said:
Use partial fractions: 1/(x2-1) = A/(x+1) + B/(x-1)

thank you very much i didn't think about that