Differential Equation/Intial Value Problem

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SUMMARY

The discussion focuses on solving the initial value problem defined by the differential equation y' = (x-y)/(x+y) with the condition y(1) = 1. The solution process involves separating variables and integrating both sides, leading to the equation 2xy + y^2 = x^2 - 2xy + C. After substituting the initial condition, the constant C is determined to be 4, resulting in the final solution 2xy + y^2 = x^2 - 2xy + 4. The participant also identifies the equation as a homogeneous differential equation.

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Homework Statement



Solve the following initial value problem,

y' = (x-y)/(x+y), y(1) = 1

Homework Equations




The Attempt at a Solution



dy/dx = (x-y)/(x+y)

dy/dx * (x+y) = x-y

(x+y)dy = (x-y)dx

∫(x+y)dy = ∫(x-y)dx

xy + y^(2)/2 = x^(2)/2 - xy + C

2xy + y^2 = x^2 - 2xy + C

y^2 + 4xy - x^2 = C

Sub in x=1, y=1

1 + 4 - 1 = C = 4

Soln: 2xy + y^2 = x^2 - 2xy + 4
 
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N/m, I just realized this is a homogeneous diffeq. Sorry.
 

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