Kinda lengthy question but bare with me please(adsbygoogle = window.adsbygoogle || []).push({});

A 1200 m3 treatment tank is used for treating effluent. The use of a particular form of algae is a major part of this process. It is important that the concentration, C, of algae not fall below 10 gm per litre as the process will not work. Above a concentration of 20 gm per litre the algae begin to die off.

Call the effective range for the concentration.

Note: We will work in terms of time in hrs, mass in gm and volume in litres.

As time passes algae are used up in the process in such a way that the rate of decrease of concentration of algae is proportional to the concentration of algae. To deal with this the algae is topped up at regular intervals of T hours. There is a special tank for growing algae from which the algae is taken.

The problem is to find the correct mass of algae to add and the time intervals at which to add it to keep the concentration as high as possible within the effective range.

1) Write the differential equation that describes the decrease in concentration of the algae. (i.e. donâ€™t worry about the top up every T hours). If the initial concentration of algae is g /l write down the initial condition.

For this as

dC/dt is proportional to C

dc/dt = kC

2) Solve your equation using separation of variables. You MUST show every step in your solution.

Next using seperation of variables i get

> dc * 1/c = k dt

> ln |C| = kt

> C = Ae^kt A = e^c

This is where im stuck how exactly do i solve this with the information give? any help would be appreciated.

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# Homework Help: Differential equation question

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