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Differential Equation: Separation of Variables

  • Thread starter brikayyy
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  • #1
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Homework Statement


dL/dp = L/2, L(0) = 100. Find the solution to the differential equation, subject to the given initial condition. My textbook says the answer is L = 100ep/2, but I don't know how to get that answer (or e for that matter).

Homework Equations


?


The Attempt at a Solution


dL/dp = L/2
L dL/dp = 1/2
∫LdL = ∫(1/2)dp
L2/2 = x/2 + C
L2 = x + 2C
(0)2 = 100 + 2C

Thanks for any help ahead of time!
 

Answers and Replies

  • #2
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I found two mistakes in your procedure. In the second step of your solution, the L on the left side should divide dL.

Then, the way to apply the initial condition is to make x=0, L=100, and solve for C. You did x=100 and L=0. D:
 
  • #3
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I found two mistakes in your procedure. In the second step of your solution, the L on the left side should divide dL.

Then, the way to apply the initial condition is to make x=0, L=100, and solve for C. You did x=100 and L=0. D:
Oh, man. D: Thanks for pointing that out!
 
  • #4
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Now that I think about it, it looks like I'm supposed to use dy/dx = ky instead of what I did in my attempt?
 
  • #5
Dick
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Now that I think about it, it looks like I'm supposed to use dy/dx = ky instead of what I did in my attempt?
You don't need a formula, you can derive the result by separation of variables. But as ymlc pointed out you are making a mistake. You should have dL/L=(1/2)dp after separating. NOT LdL=(1/2)dp. Work from there.
 
  • #6
LCKurtz
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Now that I think about it, it looks like I'm supposed to use dy/dx = ky instead of what I did in my attempt?
That equation can be solved either by separation of variables or using linear equation theory and multiplying by an integrating factor. Or, for that matter, as a constant coefficient DE if you have had that method.
 

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