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Differential Equations (Anti Derivative)

  1. Sep 19, 2007 #1
    ok im haveing trouble with this

    Find The solution (anti derivative) of y'= 1/(3y^2)

    i tired bringing up the y^2 to the top and making it (y^-2)/3 then i did the dy/dx thing and tired to move the x's and y's to one side but then i still dont get the answer. i think that i am doing something wrong in my first step. do i bring the y^2 up to y^-2?? if its wrong could you tell me what i am doing wonge. the answer is so posed to be the cube root of x + c; where c is a constant; it comes with one of the rules.
  2. jcsd
  3. Sep 19, 2007 #2

    D H

    Staff: Mentor

    Don't bring it to the top, bring it to the left. (The left of the equal sign, that is.)
  4. Sep 19, 2007 #3


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    Science Advisor
    Homework Helper

    DH is saying it's a separable differential equation. dy/dx=1/(3*y^2) so 3*y^2*dy=dx. Now integrate both sides.
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