Differential Equations (Anti Derivative)

[camboguy]

ok I am haveing trouble with this

Find The solution (anti derivative) of y'= 1/(3y^2)

i tired bringing up the y^2 to the top and making it (y^-2)/3 then i did the dy/dx thing and tired to move the x's and y's to one side but then i still don't get the answer. i think that i am doing something wrong in my first step. do i bring the y^2 up to y^-2?? if its wrong could you tell me what i am doing wonge. the answer is so posed to be the cube root of x + c; where c is a constant; it comes with one of the rules.

 

[D H]

Don't bring it to the top, bring it to the left. (The left of the equal sign, that is.)

 

[Dick]

DH is saying it's a separable differential equation. dy/dx=1/(3*y^2) so 3*y^2*dy=dx. Now integrate both sides.