Differential equations assignment T1

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SUMMARY

The discussion centers on solving the differential equation x(dy/dx) + x² = 5 with the initial condition y = 2.5 when x = 1. The solution process involves separating variables and integrating, resulting in the general solution y = 5ln(x) - (1/2)x² + c. By applying the initial condition, the constant c is determined to be 3, leading to the particular solution y = 5ln(x) - (1/2)x² + 3. The importance of verifying the solution by substituting it back into the original equation is emphasized.

PREREQUISITES
  • Understanding of differential equations and their solutions
  • Familiarity with integration techniques, particularly natural logarithms
  • Knowledge of initial value problems in calculus
  • Ability to verify solutions by substitution into original equations
NEXT STEPS
  • Study methods for solving first-order differential equations
  • Learn about initial value problems and their applications
  • Explore integration techniques involving logarithmic functions
  • Practice verifying solutions of differential equations through substitution
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Students studying calculus, particularly those focusing on differential equations, as well as educators and tutors looking for examples of solving initial value problems.

mathi85
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Hi!

I would like to ask anyone with some spare time to check my assignment questions. Last time I was asked to post one task at a time so I will.
Thank you in advance for your time.

Task 1:

Solve the differential equation: x(dy/dx)+x2=5
given that y=2.5 when x=1

Solution:

x(dy/dx)+x2=5
x(dy/dx)=5-x2 /:x
(dy/dx)=(5-x2)/(x)
∴y=∫ 5/x-x dx = 5lnx-(1/2)x2+c

General Solution:

y=5lnx-(1/2)x2+c
∴2.5=5ln(1)-(1/2)(1)2+c
∴c=3

Particular Solution:

y=5lnx-(1/2)x2+3
 
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It looks okay. I didn't see anything obviously wrong.

You can always check the answer yourself, and this is a habit you should get into. Plug it back into the original differential equation to see if it satisfies the equation. If it does and it meets the initial condition, you're done.
 
Thank you Vela!
 

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