Differential Equations initial value problem

Click For Summary
SUMMARY

The forum discussion focuses on solving the initial value problem defined by the equation 2t(dy/dt) + y = t^4 with the condition f(0) = 0. Participants suggest using an integrating factor to transform the equation into a more manageable form. Specifically, the equation can be rewritten as dy/dt + (1/2t)y = (1/2)t^3, allowing for the identification of an appropriate integrating factor. The discussion emphasizes the importance of recognizing the structure of the equation to facilitate finding the solution.

PREREQUISITES
  • Understanding of first-order linear differential equations
  • Familiarity with integrating factors in differential equations
  • Knowledge of variable separation techniques
  • Basic calculus concepts, including derivatives and integrals
NEXT STEPS
  • Study the method of integrating factors for first-order linear differential equations
  • Explore variable separation techniques in solving differential equations
  • Learn about substitution methods for simplifying differential equations
  • Practice solving initial value problems using various techniques
USEFUL FOR

Students studying differential equations, educators teaching calculus, and anyone looking to improve their problem-solving skills in mathematical analysis.

hocuspocus102
Messages
44
Reaction score
0

Homework Statement



Let f(t) be the solution to the initial value problem 2t(dy/dt)+y=t^4
with f(0) = 0
find f(t).

Homework Equations





The Attempt at a Solution



I tried to do this by separating variables but that hasn't gotten me very far. I don't know if I can do it by doing that thing where you find an integrating factor and like raising e^(some integral)? It didn't really make any sense to me when I tried it, so could someone explain it please? Thanks!
 
Physics news on Phys.org
Or a cleaver substitution? Something of the form t^\alpha y with some handy value of \alpha? Does not the left hand side of your equation look like a derivative of a something?
 
Last edited:
Because it is a linear equation, there is a formula for the "integrating factor". Write it as dy/dx+ y/2t= (1/2)t^3.

Now look for u(t) such that d(uy)/dt= u (dy/dt)+ (du/dt)y= u dy/dt+ (u/2t)y
 
Last edited by a moderator:

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K