Differential equations problem

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SUMMARY

The discussion focuses on finding functions f(x) that satisfy the condition where a curve divides rectangles formed by lines parallel to the coordinate axes into two regions with areas in a specific ratio. The solution f(x) = cx, where c is a real number, is identified as a valid function. Further analysis leads to the differential equation x(df/dx) = n f(x), which is separable and can be integrated to find additional solutions. The relationship between the areas under the curve and the rectangle is established through the equation xf(x) = (n+1)∫_0^x f(t) dt.

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  • Understanding of differential equations and their solutions
  • Familiarity with integral calculus and area under curves
  • Knowledge of separable differential equations
  • Basic concepts of Cartesian coordinates and geometric interpretations
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Homework Statement


A curve with Cartesian equation y=f(x) passes through the origin. Lines drawn parallel to the coordiante axes through and arbitrary poing of the curve form a rectangle with two sides on the axes. The curve divides every such rectangle into two regions A and B, one of which has and area equal to n times the other. Find all such functions f.


Homework Equations





The Attempt at a Solution



Obviously f(x)=cx where c is a real number works, but there must be others. Any ideas?
 
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\intydx (from 0 to x) = kxy ( for k = +- 1/n+1 or n/n+1).
This gives y = k(x y' + y) ; hence y =const. x^(1-k)
 
The area below the curve is, of course, \int_0^{x} f(t)dt while the area above the curve is \int_0^{x} f(x)- f(t) dt= xf(x)- \int_0^{x} f(t) dt Saying one is n times the other means that n\int_0^{x}f(t)dt= xf(x)- \int_0^x f(t)dt so xf(x)= (n+1)\int_0^x f(t) dt.

Differentiating both sides of that with respect to x will give you a differential equation for f(x)- xdf/dx+ f(x)= (n+1)f(x) so that xdf/dx= n f(x). That is separable and easily integrable.
 

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