1. The problem statement, all variables and given/known data Find y2 given t^2y'' + 3ty' + y = 0 y1(t) = 1/t 2. Relevant equations 3. The attempt at a solution i found y, y' and y'' and plugged it back in to the Differential equation, after doing some work, i'm basicly down to tv''+v' = 0 where y2 = v/t so u = v' and u' = v'' Plugging that in... tu' + u = 0 how would i solve this for u? i think its separable equations but that would give me du/-u = dt/t which would be ln (u) = -ln(t) + c .... u = 1/t +c so v' = 1/t +c which means v = lnt pluging v into y2 would give me lnt/t Sorry its kind of confusing but the answer's not in the back of the book and i need to know if i did this right Thank you!