- #1
b200w
- 4
- 0
Okay this is the second time writing this out, hopefully it won't log me out again...
Given:
dy/dx = (e^y * sin^2(x))/(y*sec(x))
I separated out and integrated the y side using parts (for brevity's sake I won't repeat the math here as it's straightforward and presumably correct). I currently have this:
-(y+1)/e^y = INT[ sin^2(x)/sec(x) dx ]
My problem is I've never been able to completely grasp trig relations and I'm probably just missing something obvious but I spent an hour combing my book and previous homework assignments and I can't find a clue where to start. If someone could point me in the right direction I'll presumably be off and running. How would I integrate the RHS of the equation?
Given:
dy/dx = (e^y * sin^2(x))/(y*sec(x))
I separated out and integrated the y side using parts (for brevity's sake I won't repeat the math here as it's straightforward and presumably correct). I currently have this:
-(y+1)/e^y = INT[ sin^2(x)/sec(x) dx ]
My problem is I've never been able to completely grasp trig relations and I'm probably just missing something obvious but I spent an hour combing my book and previous homework assignments and I can't find a clue where to start. If someone could point me in the right direction I'll presumably be off and running. How would I integrate the RHS of the equation?