Differential Equations: word problem

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The discussion focuses on solving a cooling problem using Newton's law of cooling, where the temperature of a cake is modeled as it cools from 300 degrees F to 75 degrees F. The initial equation dx/dt = k(x-70) is critiqued, emphasizing that it should be written as dx/dt = -k(x-70) to ensure a positive k value, reflecting the cooling process correctly. The calculations lead to the conclusion that the time to cool to 75 degrees is approximately 20 minutes. Participants clarify that the transient state should approach zero as time increases, reinforcing the importance of correctly interpreting the cooling equation. Overall, the discussion highlights the mathematical and physical considerations necessary for accurately modeling cooling scenarios.
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Homework Statement



When a cake is removed from an oven, its temperature is measured at 300 degrees F, 3 min later its 200, how long will it take for it to cool off to 75? room temp is 70. Assume Newtons law of cooling applies. The rate of cooling is proportional to the difference between the current temp and the ambient temp.


Homework Equations



This is what i did:
dx/dt = k(x-70)

The Attempt at a Solution



dx/dt = k(x-70)
integral 1/(x-70) dx = integral k dt
ln|x-70| = kt+c
after some algebra...
x = C*e^(kt) +70 where C = + or - e^c
at x(o) = 300 so...
300 = C*e^(k*0) +70
which gives me C = 230

x(t) = 230*e^(kt) +70
x(3) = 200
200 =230*e^(k*3) +70
k = 1/3 * ln(13/23)

now that i have an equation i can solve for the time it takes to get to 75
i'll leave k as k since its confusing when put into the equation
75 = 230*e^(kt) +70
i solved and got
t = (3*ln(5/230))/(ln(13/23))
which is approximately 20 minutes

Did i do this right? or did i go wrong somewhere, i just want to make sure I am getting the right idea with these kinds of problems
 
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mathematically i find no mistake

but physically speaking we are formulating an equation for cooling so it is better to write the equation as
dx/dt = -k(x-70)
so that you will get a positive k value in the end of the calculation

because if k value is given as positive in the problem
your steady state result would tend to infinity instead of room temp 70.
x = C*e^(kt) +70
 
payumooli said:
mathematically i find no mistake

but physically speaking we are formulating an equation for cooling so it is better to write the equation as
dx/dt = -k(x-70)
so that you will get a positive k value in the end of the calculation

because if k value is given as positive in the problem
your steady state result would tend to infinity instead of room temp 70.
x = C*e^(kt) +70
No, it does not- his k is (1/3)ln(13/23), a negative number.
 
what i wanted to convey is these solutions have a steady state and transient state.

the transient state should tend to zero when time approaches infinty.(for this cooling problem)

x(t) = 230*e^(kt) +70, k<0 should be the solution if you have right idea about this problem
 
Thank you so much. I didn't think it would make a difference if it was -k or not because i saw an example somewhat similar to this in the book I'm using and it had a positive k. The answer just looked very confusing so i wanted to make sure i doing the question right
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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