- #1

rollingstein

Gold Member

- 646

- 16

dW=Pd

^{2}V

I think this doesn't make any sense mathematically; but I wanted to check. Is this mathematically meaningful at all?

This I understand:

dW=PdV

W=∫PdV

But for dW=Pd

^{2}V I cannot see how one could proceed.

Here V is an independent variable; P=f(V).