Differentials and paint needed problem

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Homework Help Overview

The problem involves estimating the amount of paint needed to coat a hemispherical dome with a specific thickness using differentials. The subject area is calculus, specifically focusing on differentials and volume calculations related to geometric shapes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between area and volume in the context of applying paint to a hemispherical shape. There is an exploration of the appropriate formulas for volume and differentiation, with some participants questioning the correctness of their calculations and assumptions.

Discussion Status

The discussion is ongoing, with participants providing guidance on the correct formulas for volume and differentiation. There is recognition of the need to differentiate between the volume of a sphere and a hemisphere, and some participants are attempting to clarify their understanding of the differentiation process.

Contextual Notes

There is a noted confusion regarding the application of differentials to volume versus area, as well as the correct differentiation of the volume formula. Participants are also addressing the implications of a small change in radius on the volume calculation.

synergix
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Homework Statement



Use differentials to estimate the amount of paint needed to apply a coat of paint 0.05cm thick to a hemispherical dome with diameter 50m

Homework Equations



A= 2(pi)r2

The Attempt at a Solution



dr=0.0005 m
r=25m
dA=?

(A=2(pi)r2)'

dA= 4(pi)r*dr

I won't go any further because the number is very small and i think incorrect.
I am pretty sure I'm missing a step but I can't figure out what or why.
Then again I could be way off.
 
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the amount of paint will be a volume, not area, think of a thin spherical shell
 


What is the formula for volume of a sphere?

(\pi r^2 is the area of circle and not relevant here.)
 


volume of a sphere= (4/3)pi*r^2

volume of hemisphere= (4/6)pi*r^2

dv= (4/3)pi*r*dr

dv= (4/3)*pi*25*.0005

am I wrong still?
 


synergix said:
volume of a sphere= (4/3)pi*r^2

volume of hemisphere= (4/6)pi*r^2

dv= (4/3)pi*r*dr

dv= (4/3)*pi*25*.0005

am I wrong still?

yes...

volume of a sphere is (4/3)pi*r^3

and when you differntiate a power, you multiply by the orgiginal power, not divide
 


that looks like the whole sphere, how about the hemisphere part?
 


dv=2pi*r^2
 


almost... you just need to add a dr in there

so to sumamrise
V(r) = (1/2)(4/3)pi.r^3 = (2/3)pi.r^3

then the derivative is
dV/dr = 2pi*r^2

so for a small change in r, ∆r the approximate corresponding change in ∆V volume will be
∆V= (dV/dr).∆r = 2pi.r^2.∆r
 

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