Differentials and Rates of Change; Related Rates

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Homework Help Overview

The discussion revolves around a problem related to differentials and rates of change, specifically focusing on the volume of a cylinder and how it changes with respect to time as the radius and height vary. Participants are examining the relationships between the rates of change of volume, radius, and height.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply the product rule and implicit differentiation to find the rate of change of volume with respect to time. There is confusion regarding whether to find dr/dt or dV/dt, with some suggesting that the problem requires calculating dV/dt for given rates of change.

Discussion Status

There is ongoing clarification about the correct interpretation of the problem, with multiple participants questioning the assumptions regarding what needs to be calculated. Some guidance has been offered regarding the implications of the volume being constant, but no consensus has been reached on the final answer.

Contextual Notes

Participants note that the volume is given as constant, which raises questions about the value of dV/dt. There is also mention of a multiple-choice format for the problem, which influences the approach to finding the solution.

Qube
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Homework Statement



http://i4.minus.com/jboxzSadIJVVoi.jpg

Homework Equations



Product rule; implicit differentiation.

Volume of cylinder, V = pi(r^2)(h)

The Attempt at a Solution



dV/dt = 0 = pi[2r(dr/dt)(h) + (dh/dt)(r^2)]

Solve the equation after plugging in r = 5; h = 8, and dh/dt = -2/5. Solve for dr/dt.

0 = 80pi(dr/dt) - 10pi

1 = 8(dr/dt)

dr/dt = 1/8
 
Last edited by a moderator:
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You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).
 
elvishatcher said:
You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).

It says to find the rate of change of the radius in the first part of the question.

I think you just have to have it like this: \frac{dV}{dt}=2\pi r\frac{dr}{dt}\frac{dh}{dt}, then just plug in values.

Edit: Oh forgot to add, the V is constant, so what does that mean the value of dV/dt is?
 
Last edited:
elvishatcher said:
You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).
It's multiple choice. V is given as constant, dh/dt is a given value, so the obvious approach is to calculate dr/dt and see which choice matches. Of course, you could run it the other way: for each choice compute dV/dt and see which one gives 0, but that probably takes longer on average.
iRaid said:
the dV/dt is constant, so what does that mean the value of it is?
You mean V is constant, so what value is dV/dt, right?
 
haruspex said:
It's multiple choice. V is given as constant, dh/dt is a given value, so the obvious approach is to calculate dr/dt and see which choice matches. Of course, you could run it the other way: for each choice compute dV/dt and see which one gives 0, but that probably takes longer on average.

You mean V is constant, so what value is dV/dt, right?

Yes, my mistake.
 
Is 1/8 the correct answer? I've redone the work again below:
 
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Qube said:
Is 1/8 the correct answer? I've redone the work again below:

Yes.
 

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