Differentials and Rates of Change; Related Rates

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SUMMARY

The discussion centers on solving a related rates problem involving the volume of a cylinder, defined by the equation V = π(r²)(h). Participants utilized the product rule and implicit differentiation to derive the rate of change of volume (dV/dt) while considering the radius (r) and height (h) of the cylinder. The specific values used were r = 5, h = 8, and dh/dt = -2/5. The final conclusion confirmed that dr/dt equals 1/8, affirming the calculations and the understanding of the problem's requirements.

PREREQUISITES
  • Understanding of related rates in calculus
  • Familiarity with the product rule in differentiation
  • Knowledge of implicit differentiation techniques
  • Basic concepts of volume calculation for geometric shapes, specifically cylinders
NEXT STEPS
  • Study the application of the product rule in more complex related rates problems
  • Explore implicit differentiation with varying geometric shapes
  • Learn how to derive and interpret dV/dt in different contexts
  • Practice solving related rates problems using real-world scenarios
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Students and educators in calculus, particularly those focusing on related rates and differentiation techniques. This discussion is beneficial for anyone looking to deepen their understanding of volume changes in geometric contexts.

Qube
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Homework Statement



http://i4.minus.com/jboxzSadIJVVoi.jpg

Homework Equations



Product rule; implicit differentiation.

Volume of cylinder, V = pi(r^2)(h)

The Attempt at a Solution



dV/dt = 0 = pi[2r(dr/dt)(h) + (dh/dt)(r^2)]

Solve the equation after plugging in r = 5; h = 8, and dh/dt = -2/5. Solve for dr/dt.

0 = 80pi(dr/dt) - 10pi

1 = 8(dr/dt)

dr/dt = 1/8
 
Last edited by a moderator:
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You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).
 
elvishatcher said:
You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).

It says to find the rate of change of the radius in the first part of the question.

I think you just have to have it like this: \frac{dV}{dt}=2\pi r\frac{dr}{dt}\frac{dh}{dt}, then just plug in values.

Edit: Oh forgot to add, the V is constant, so what does that mean the value of dV/dt is?
 
Last edited:
elvishatcher said:
You are not trying to find \frac{dr}{dt}. Each part of the question wants you to find \frac{dV}{dt} for a given rate at which the radius is changing (think about what represents the rate of change of the radius).
It's multiple choice. V is given as constant, dh/dt is a given value, so the obvious approach is to calculate dr/dt and see which choice matches. Of course, you could run it the other way: for each choice compute dV/dt and see which one gives 0, but that probably takes longer on average.
iRaid said:
the dV/dt is constant, so what does that mean the value of it is?
You mean V is constant, so what value is dV/dt, right?
 
haruspex said:
It's multiple choice. V is given as constant, dh/dt is a given value, so the obvious approach is to calculate dr/dt and see which choice matches. Of course, you could run it the other way: for each choice compute dV/dt and see which one gives 0, but that probably takes longer on average.

You mean V is constant, so what value is dV/dt, right?

Yes, my mistake.
 
Is 1/8 the correct answer? I've redone the work again below:
 
utevyruh.jpg
 
Qube said:
Is 1/8 the correct answer? I've redone the work again below:

Yes.
 

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