Differentials: Population moving model

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Homework Help Overview

The problem involves a population model divided into rural and urban groups, where individuals move between these areas at specified rates. The original poster seeks to derive a new variable representing the fraction of the population in rural areas and to find steady states and stability conditions for this variable.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the relationship between the fraction Z(t) and the total populations R(t) and U(t), expressing confusion about deriving Z(t). Other participants clarify the definition of Z(t) as a proportion of the total population and suggest a formula for it. There are also inquiries about the derivation of the differential equation for Z(t).

Discussion Status

Contextual Notes

missavvy
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Homework Statement


The population of a country is divided in two groups:

People who live in rural areas (R(t)) and people who live in urban areas (U(t)).
People move from rural to urban areas with a rate m and from
urban to rural areas with rate n.

a) Introduce the fraction of people (Z(t)) who live in rural
areas as a new variable and derive an equation for it.

b) Find the steady state(s) of the equation for Z and the
stability condition.

Homework Equations


R' = −mR + nU
U' = mR − nU.


The Attempt at a Solution



a) So I don't really get this, but is the fraction Z(t) different from R(t)??
Anyways, I think it goes:
Z(t) = R(t) - U(t) / R(t)
how would i go about deriving it?

I am extremely confused. If anyone can just somehow reword it or something so that I can understand it that would be great.

b) If I could get Z(t) into differential form I can easily find the steady state, by just setting it = to 0.. so my problem really lies in the first part.
 
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the fraction of people who live in the rural area should be
Z(t) = R(t) /(R(t)+U(t))
 
Z' = -mZ + n(1-Z)

you can take from here
 
Welcome to PF!

missavvy said:
The population of a country is divided in two groups:

People who live in rural areas (R(t)) and people who live in urban areas (U(t)).
People move from rural to urban areas with a rate m and from
urban to rural areas with rate n.

a) Introduce the fraction of people (Z(t)) who live in rural
areas as a new variable and derive an equation for it.

a) So I don't really get this, but is the fraction Z(t) different from R(t)??

b) If I could get Z(t) into differential form I can easily find the steady state, by just setting it = to 0.. so my problem really lies in the first part.

Hi missavvy! Welcome to PF! :smile:

You're confusing totals with proportions.

R and U are totals, Z is only a proportion …

so just ask yourself, what two things is it a proportion of? :wink:
 
ah sorry i meant z= r/r + u!
thanks tiny-tim! yeah that's what i had thought but I wasn't sure, thanks for clarifying that :)
 
payumooli said:
Z' = -mZ + n(1-Z)

you can take from here

Just wondering how did you derive the Z(t)?
Did you derive Z(t) = R(t) / R(t) + U(t), and then just plug in the R' and U' for those values?
 

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